1.55 / 1 = x / 3.5....$ 1.55 to 1 lb = $ x to 3.5 lbs
first one <==
it could have also been : 1 / 1.55 = 3.5 / x...but that is not an answer choice
Answer:
![4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%204x%5E5%5Csqrt%5B3%5D%7B3x%7D%20)
Step-by-step explanation:
I'm not sure I understand the problem, but I think it's this:
![\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} =](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B16x%5E7%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B12x%5E9%7D%20%3D%20)
![= \sqrt[3]{16 \times 12 \times x^{16}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B16%20%5Ctimes%2012%20%5Ctimes%20x%5E%7B16%7D%7D)
![= \sqrt[3]{192 \times x^{15} \times x}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B192%20%5Ctimes%20x%5E%7B15%7D%20%5Ctimes%20x%7D)
![= \sqrt[3]{64 \times 3 \times (x^5)^3 \times x}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B3%5D%7B64%20%5Ctimes%203%20%5Ctimes%20%28x%5E5%29%5E3%20%5Ctimes%20x%7D%20)
![= \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B3%5D%7B4%5E3%20%5Ctimes%203%20%5Ctimes%20%28x%5E5%29%5E3%20%5Ctimes%20x%7D%20)
![= 4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%20%3D%204x%5E5%5Csqrt%5B3%5D%7B3x%7D%20)
E=13,000 and<span>E=1/50R(1650-R)</span>
<span>
</span>
<span />0.02R(1650-R)=13000
<span>(0.02R)(1650)-0.02R²=13000</span>
<span /><span>0.02R²-33R+13000=0</span>
<span>R2-1650R+650000=0</span>
<span>SOLVE W QUAD FORMULA
</span>
Answer:
12
Step-by-step explanation:
Well, 12/12=1, which I guess is the smallest number we can get, and 12 is divisible by 2 too.
