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kicyunya [14]
2 years ago
11

In January of 2003(group 1), 1188 out of 1500 spots were bare ground (no vegetation). Find the sample proportion of bare ground

spots.
Mathematics
1 answer:
Nikitich [7]2 years ago
7 0

Answer:

n= 1500 represent the random sample selected

X= 1188 represent the number of pots that were bare ground (no vegetation

\hat p=\frac{X}{n}

And replacing we got:

\hat p=\frac{1188}{1500}= 0.792

So then the sample proportion of bare ground spots is 0.792 for this sample

Step-by-step explanation:

We have the following info given from the problem:

n= 1500 represent the random sample selected

X= 1188 represent the number of pots that were bare ground (no vegetation)

And for this case if we want to find the sample proportion of bare ground spots we can use this formula:

\hat p=\frac{X}{n}

And replacing we got:

\hat p=\frac{1188}{1500}= 0.792

So then the sample proportion of bare ground spots is 0.792 for this sample

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Step-by-step explanation:

The question is wrong. The correct equation is :

C=\frac{5}{9}F-\frac{160}{9}

We know that the equation gives the relation  between temperature readings in Celsius and Fahrenheit.

Therefore, giving that we know the value in Fahrenheit ''F'' we can find the reading in Celsius ''C''. This define a function C(F) that depends of the variable ''F''.

So for the incise (a) we answer Yes, C is a function of F.

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Dom (C) = ( - ∞ , + ∞)

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For C = 0 :

0=\frac{5}{9}F-\frac{160}{9} ⇒ F=32

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Therefore, the domain as relating temperatures of water in its liquid state is

Dom (C) = (32,212)

For (d) we only need to replace in the equation by F=71 and find the value of C ⇒

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C=(\frac{5}{9})(71)-\frac{160}{9}

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Check the explanation

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(a)

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Kindly check the graphical table in the attached images below.

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