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belka [17]
2 years ago
8

290 pennies are equal to how many dimes

Mathematics
2 answers:
ExtremeBDS [4]2 years ago
6 0
29 dimes
............
Delicious77 [7]2 years ago
4 0
29 dimes because 10 times 29 equals 290
You might be interested in
If 15% of the customer's total is $22.05, then the customer's total is
Harrizon [31]

<u>Answer</u>:  If 15% of the customer's total is $22.05, then the customer's total is <u>$147</u>.

<u>Step-by-step explanation</u>:

Let x be the customer's total amount.

It is given that 15% of the customer's total = $22.05

⇒15% of x= $22.05

\Rightarrow0.15x=\$22.05\\\\\text{Divide 0.15 on both sides, we get}\22.05\\\\\Rightarrow x=\frac{22.05}{0.15}\\\\\Rightarrow x=\$147

Therefore, If 15% of the customer's total is $22.05, then the customer's total is <u>$147</u>.

6 0
2 years ago
Read 2 more answers
A standardized test consists of 100 multiple-choice questions. Each question has five possible answers, only one of which is cor
Nady [450]

Answer:

a) S ~ N ( 0 , 48 )

b) P ( S > 10 ) = 0.0745

Step-by-step explanation:

Given:-

- We have n = 100 MCQs

- 5 options for every MCQs

- probability to guess each MCQ correct is independent from one another.

- Right Answer points= +4

- Wrong answer points= -1

Find:-

a) Find ????(S).

b) Find P(S>10). Write your answer as a math expression, then use the code cell below to find its numerical value and provide it along with your math expression.

Solution:-

- The probability (p) of guessing a correct answer for each question is:

                             p ( correct answer ) = 1 / 5 = 0.2

- The mean number of correct and incorrect answers can be determined by:

                             ( Mean correct answers) = n*p = 100*0.2 = 20

                             ( Mean incorrect answers) = n*(1-p) = 100*0.8 = 80

- The mean score for correct answers would be:

                            Sc ( u ) = (Points for right answer)*(Mean correct answers)

                            Sc ( u ) = ( +4 )*(20)

                            Sc ( u ) = 80 points

The mean score for incorrect answers would be:

                            Si ( u ) = (Points for wrong answer)*(Mean incorrect answers)

                            Si ( u ) = ( -1)*(80)

                            Si ( u ) = -80 points.

- The mean score attained by a student would be S (u):

                           S (u) = Sc(u) + Si(u)

                           S (u) = 80 - 80 = 0

- The variance of the correct and incorrect answers can be determined by:

                           Var ( correct answers ) = n*p*q = 100*0.2*0.8 = 16

                           Var ( in-correct answers ) = n*p*q = 100*0.2*0.8 = 16

- The variance of points of correct answers can be:

                           Sc (Var) = Var ( correct answer ) * (Points for right answer)

                           Sc (Var) = 16*(+4) = +64 points

- The variance of points of incorrect answers can be:    

                          Si (Var) = Var ( incorrect answer ) * (Points for wrong answer)

                          Si (Var) = 16*(-1) = -16 points  

- Since the probabilities of guessing correct answers are independent. Then as per law of independence:

                         S ( Var ) =  Sc (Var) + Si (Var)

                                       = 64 - 16

                                       = +48 points

- The standard deviation for the distribution (s.d) of points (S) is:

                         S ( s.d ) = √S (Var)  = √48 = 6.9282            

- The number of points (S) attained by a student by guessing on the test containing MCQs would have a mean u = 0 points and s.d = + 48 points.

- The random variable (S) can be modeled by normal distribution as follows:

                         S ~ N ( 0 , 48 )      

- To find the required probability P(S>10).

Compute the Z-value of S = 10 points:

                        Z - value =  ( S - u ) / s.d

                                        =  ( 10 - 0 ) / 6.9282

                                        = 1.4434

Use the standardized Z-table for normal distribution:

                       P ( Z > 1.4434 ) = 0.0745

The probability is:

                       P ( S > 10 ) = P ( Z > 1.4434 ) = 0.0745

5 0
2 years ago
This form will be sent to Lily by the end of January. She will use this W-2 form to...
yKpoI14uk [10]

Answer:

D-FIle her income taxes

Step-by-step explanation:

7 0
1 year ago
An oil company claims that the sulfur content of its diesel fuel is at most .15 percent. To check this claim, the sulfur content
GarryVolchara [31]

Answer:

No, it would have to have been greater than .192 to invalidate the claim.

Step-by-step explanation:

3 0
2 years ago
The inside diameter of a randomly selected piston ring is a random variable with mean value 13 cm and standard deviation 0.08 cm
sweet-ann [11.9K]

Answer:

a) P(12.99 ≤ X ≤ 13.01) = 0.3840

b) P(X ≥ 13.01) = 0.3075

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the cental limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 13, \sigma = 0.08

(a) Calculate P(12.99 ≤ X ≤ 13.01) when n = 16.

Here we have n = 16, s = \frac{0.08}{\sqrt{16}} = 0.02

This probability is the pvalue of Z when X = 13.01 subtracted by the pvalue of Z when X = 12.99.

X = 13.01

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{13.01 - 13}{0.02}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

X = 12.99

Z = \frac{X - \mu}{s}

Z = \frac{12.99 - 13}{0.02}

Z = -0.5

Z = -0.5 has a pvalue of 0.3075

0.6915 - 0.3075 = 0.3840

P(12.99 ≤ X ≤ 13.01) = 0.3840

(b) How likely is it that the sample mean diameter exceeds 13.01 when n = 25?

P(X ≥ 13.01) =

This is 1 subtracted by the pvalue of Z when X = 13.01. So

Z = \frac{X - \mu}{s}

Z = \frac{13.01 - 13}{0.02}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

1 - 0.6915 = 0.3075

P(X ≥ 13.01) = 0.3075

7 0
2 years ago
Read 2 more answers
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