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2 years ago

Help me with this question!!!

Mathematics

2 answers:

qwelly [4]2 years ago

6 0

Step-by-step explanation:

×=100

1. Divded 35 by 14 and u get 0.4

Divided 40 by 0.4 and u get 100

suter [353]2 years ago

6 0

Answer:

Step-by-step explanation:

You could solve it two ways:

Cross multiply:

x times 35 = 35x

40 times 14 = 560

35x divided by 35 = x

560 divided by 35 = 16

x = 16

Or:

35 divided by 14 = 2.5

40 divided by 2.5 = 16

x = 16

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2 years ago

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"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r

sergiy2304 [10]

Answer:

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

Let $p_1$ = proportion of drivers that were in compliance initially

$p_2$ = proportion of drivers that were in compliance one year later

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$ {means that there is not any statistical difference in these two proportions measured initially and then one year later}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$ {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of drivers in compliance initially = 98.9%

$\hat p_2$ = sample proportion of drivers in compliance one year later = 96.9%

$n_1$ = sample of drivers initially = 1,250

$n_2$ = sample of drivers one year later = 1,100

(b) So, the test statistics = $\frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }$

= 3.33

Now, P-value of the test statistics is given by;

P-value = P(Z > 3.33) = 1 - P(Z $\leq$ 3.33)

= 1 - 0.99957 = 0.00043

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

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2 years ago

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2 years ago

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Answer:

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Step-by-step explanation:

Let

t ------> is the number of minutes he spends on each scale

Remember that the phrase "at least" is equal to "greater than or equal"

The inequality that represent this scenario is

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$-5t \geq -15$

Multiply by -1 both sides

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Sven is incorrect

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2 years ago

In the diagram, transversal t cuts across the parallel lines a and b. Match the pairs of angles with the relationship that shows

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we know that

case a) alternate exterior angles

m∠2=m∠7 --------> by alternate exterior angles

m∠1=m∠8 --------> by alternate exterior angles

case b) alternate interior angles

m∠3=m∠6 --------> by alternate interior angles

m∠5=m∠4 --------> by alternate interior angles

case c) corresponding angles

m∠1=m∠5 --------> by corresponding angles

m∠3=m∠7 --------> by corresponding angles

m∠2=m∠6 --------> by corresponding angles

m∠4=m∠8 --------> by corresponding angles

case d) vertical angles

m∠1=m∠4 --------> by vertical angles

m∠2=m∠3 --------> by vertical angles

m∠5=m∠8 --------> by vertical angles

m∠6=m∠7 --------> by vertical angles

therefore

the answer in the attached figure

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2 years ago