Answer:
The correlation coeffcient for this case was provided:
r =0.934
And this coefficient is very near to 1 the maximum possible value, so then we can interpret that the relationship between the entrace exam score and the grade point average are strongly linearly correlated .
We can also find the
who represent the determination coefficient and we got:

And the interpretation for this is that a linear model explains appproximately 87.2% of the variability between the two variables
Step-by-step explanation:
Previous concepts
The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.
And in order to calculate the correlation coefficient we can use this formula:
The correlation coeffcient for this case was provided:
r =0.934
And this coefficient is very near to 1 the maximum possible value, so then we can interpret that the relationship between the entrace exam score and the grade point average are strongly linearly correlated .
We can also find the
who represent the determination coefficient and we got:

And the interpretation for this is that a linear model explains appproximately 87.2% of the variability between the two variables
A 120 watt light bulb uses about 0.1 kilowatt of electricity per hour.if electricity costs $0.20 per kilowatt hour.
Let's solve how much does it cost to have a bulb on
for an hour.
=> 120 watt = 0.1 kilowatt per hour which costs 0.20 per kilowatt per
=> 0.1 kilowatt per hour * 0.20 = 0.02 dollars in an hour.
First find the tangent line
dy/dx=2x
at x=6, the slope is 2(6)=12
so
use point slope form
y-y1=m(x-x1)
point is (6,36)
so
y-36=12(x-6)
y-36=12x-72
y=12x-36
alright, so we know they intersect at x=6
and y=12x-36 is below y=x^2
so we do


the area under the curve bounded by the lines and the x axis is 72 square units
Answer:
Total amount of water = 5,200,000
Step-by-step explanation:
Given:
water produced = 50,000 quarts of water per week
Production drop = 5% = 0.05 per year
Number of week in year = 52 week
Find:
Total amount of water
Computation:
Sum = a / r
a = 50,000 x 52
a = 2,600,000
Sum = a / [1-r]
Sum = 2,600,000 / 5%
Sum = 2,600,000 / 0.05
Total amount of water = 5,200,000