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Sergio039 [100]
2 years ago
9

Chris rents a car for a total of £375. The rental charges are £150 for the first day and £75 per day after that. For how many da

ys did Chris rent the car? You must show your working.
I have attempted the question (see picture), but I've only managed to get 2/3 marks!!! Please help! (I will award brainliest btw) TIA ;-)​

Mathematics
1 answer:
Vsevolod [243]2 years ago
7 0

9514 1404 393

Answer:

  4 days

Step-by-step explanation:

The total charges can be modeled by ...

  c = 75d + 75 . . . . . . charges for d days

Filling in the given charge, we find ...

  375 = 75d +75

  300 = 75d . . . . . . . subtract 75

  4 = d . . . . . . . . . . divide by 75

Chris rented the car for 4 days.

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The law of cosines is a^2+b^2-2abcosC=c^2. Find the value of 2abcosC.
polet [3.4K]
2ab x cos (C) = 7 because

a^2 + b^2 - 2ab x cos(C) = c^2
2ab x cos(C) = a^2 + b^2 - c^2
2ab x cos(C) = 2^2 + 2^2 - 1^2
2ab x cos (C) = 7
4 0
2 years ago
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The weight of a box of cereal can vary by of an ounce and still be sold as a full box. Each box is supposed to contain 18 ounces
mezya [45]

Answer:

If a box is supposed to contain 18 ounces, and the acceptable error is 1 ounce, then the acceptable range is:

18 oz - 1oz = 17oz to 18oz + 1oz = 19oz

Then the acceptable range is (17oz, 19oz)

if the weight is smaller than 17 oz, the box is not acceptable.

If the weight is bigger than 19 oz, the box is not acceptable.

Then the graph of the boxes that can not be sold as full boxes is:

<---16---------17-------18--------19-------20----------->

where 17oz and 19oz are not included, because are acceptable weigths.

8 0
2 years ago
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Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a)
Salsk061 [2.6K]

Answer:

a) 1 tsp.

b) 1.5 tsp.

c) 2 tsp.

Step-by-step explanation:

Complete Correct Question

Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog

- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

Solution

a) 18 kg adult dog

The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

9 kg dog weight = (1/2) tsp

18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.

b) 6 kg cat

The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

1 kg cat = (1/4) tsp

6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.

c) 18 kg pregnant dog

The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

4.5 kg dog weight = (1/2) tsp

18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.

Hope this Helps!!!

4 0
2 years ago
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Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well
laiz [17]

Answer:

The  value is  P(A) =  0.133617

Step-by-step explanation:

From the question we are told that

  The  mean is  \mu =  7.5

  The standard deviation is  \sigma  =  0.2

  The safest water level is  between  7.2 and  7.8

Generally the probability that the selected pool has a pH level that is not considered safe is mathematically represented as

       P(A) =  1 - P(7.2 \le X  \le 7.8 )

Here  

      P(7.2 < X  < 7.8 ) = P(\frac{ 7.2 - \mu }{\sigma } <  \frac{X - \mu }{ \sigma }

Generally \frac{X - \mu }{ \sigma } =  Z (The  \ standardized \  value  \  of  X )

So

 P(7.2 < X  < 7.8 ) = P(\frac{ 7.2 - 7.5 }{0.2 } < Z    

 P(7.2 < X  < 7.8 ) = P(-1.5 < Z  

=>  P(7.2 < X  < 7.8 ) = P(Z <  1.5) - P(  Z < - 1.5)

From the z-table the probability of  (Z <  -1.5) and   (  Z <1.5)  are

    P(Z <  1.5) =  0.93319

and  

    P(Z <  -1.5) =  0.066807

So

      P(7.2 < X  < 7.8 ) =0.93319 - 0.066807

       P(7.2 < X  < 7.8 ) =0.0866383

So

   P(A) =  1 - 0.0866383

=>  P(A) =  0.133617

5 0
2 years ago
Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of cracke
Anna11 [10]

Answer:

The cost of a box of crackers is $2.25.

Step-by-step explanation:

Let the cost of a containers of yogurt is $x and cost of a box of crackers is $y.

It is given that Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55.

4x+3y=9.55              .... (1)

She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90.

2x+2y=5.90              .... (2)

On solving (1) and (2), using graphing calculator, we get

x=0.7

y=2.25

Therefore the cost of a box of crackers is $2.25.

6 0
2 years ago
Read 2 more answers
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