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Anton [14]
2 years ago
7

A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions o

f the first garden. What is the percent of change in perimeter from the first garden to the second garden?
Mathematics
1 answer:
sergey [27]2 years ago
5 0

Answer:

100 percent increase

Step-by-step explanation:

1st garden

Length = 6 ft

Width = 4 ft

Perimeter = 2 (l+w)

                 = 2 (6+4) = 2(10) = 20

2nd garden

The length and width are 2 times the 1st garden

Length = 2 *6 = 12

Width = 2 *4 = 8

Perimeter = 2 (l+w)

                 = 2 (12+8) = 2(20) = 40

Percent change = (new - old )/old * 100 percent

The 1st garden is the old garden = 20  and the 2nd garden is the new garden = 40

Substituting in

Percent change = (40-20)/20 = 20/20 =100 *100 percent

                            = 100 percent increase

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I am Lyosha [343]

Answer:

$43.75

Step-by-step explanation:

So you have: 35% discount

Total without discount: $125.00

Amount discounted: ?

So you have to make 35% into a number that you can multiply with $125. When you have a percentage you move the decimal two times to the front so you have 0.35 then you multiply;

125 x 0.35 = 43.75.

43.75 is the amount discounted, so you only have to pay 81.25. The equation for that would look like;

125 - 43.75 = 81.25

Hope that made sense!

7 0
2 years ago
The total distance in centimeters that a toy robot moves varies directly with the time in seconds the toy robot moves a total di
kobusy [5.1K]

Answer:

Hey there!

The robot moves 63 cm in 9 seconds. Then in 1 second, it moves 7 cm.

If it goes 49 cm, it will take 7 seconds.

Let me know if this helps :)

4 0
2 years ago
Reyna has 5 coins worth 10 cents each and 4 coins
Zolol [24]

Answer:

The Probability found is:

P =  \frac{13}{18}

Step-by-step explanation:

Let x be the 10 cents coin.

Let y be the 25 cents coin.

We have to find all the possible outcomes

1) First coin = 10 cents, Second coin = 10 cents , so

(x,x) = 20

2) First coin = 10 cents, Second coin = 25 cents , so

(x,y) = 35

3) First coin = 25 cents, Second coin = 10 cents , so

(y,x) = 35

4) First coin = 25 cents, Second coin = 25 cents , so

(y,y) = 50

Find the probability of each outcome:

P(x,x) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(x,y) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(y,x) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(y,y) = \frac{4}{9}\cdot\frac{3}{8}=\frac{12}{72}

Add all the probabilities where sum is at least 35 i.e P(x,y) , P(y,x) , P(y,y)

P(x,y) + P(y,x) + P(y,y) = \frac{20}{72}+\frac{20}{72}+\frac{12}{72} = \frac{52}{72}=\frac{13}{18}\\

6 0
2 years ago
Use known facts to find 9x5
Charra [1.4K]
If your asking to multiply 9x5 then the anwser is 45.
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2 years ago
Complete the square to solve the equation below x^2 + 10x - 13 = 17
liberstina [14]

Answer:

See below in exact form

or

2.42, -12.42   to the nearest hundredth.

Step-by-step explanation:

x^2 + 10x - 13 = 17

(x + 5)^2 - 25 - 13 = 17

(x + 5)^2 = 17 + 38 = 55

x + 5 = +/- √55

x =  -5 + √55,  -5 - √55.

6 0
2 years ago
Read 2 more answers
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