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Anton [14]
2 years ago
7

A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions o

f the first garden. What is the percent of change in perimeter from the first garden to the second garden?
Mathematics
1 answer:
sergey [27]2 years ago
5 0

Answer:

100 percent increase

Step-by-step explanation:

1st garden

Length = 6 ft

Width = 4 ft

Perimeter = 2 (l+w)

                 = 2 (6+4) = 2(10) = 20

2nd garden

The length and width are 2 times the 1st garden

Length = 2 *6 = 12

Width = 2 *4 = 8

Perimeter = 2 (l+w)

                 = 2 (12+8) = 2(20) = 40

Percent change = (new - old )/old * 100 percent

The 1st garden is the old garden = 20  and the 2nd garden is the new garden = 40

Substituting in

Percent change = (40-20)/20 = 20/20 =100 *100 percent

                            = 100 percent increase

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A pipe of diameter 64mm discharges water at a rate of 2.05mm/s into an empty cylindrical tank of diameter 7.6cm and height 2.3m.
inessss [21]

Answer:

Diameter of pipe = D = 64mm

cross sectional Area of pipe= A = pi * (D/2)^2 = pi * (32)^2 = 1024pi  mm^2

Discharge Rate of water = v = 2.05 mm/s

Volume of Cylinder = V = pi * (D/2)^2 * h = pi * (38)^2 * 2300 = 3321200pi  mm^3

(Area of pipe)*(Rate) = (Volume) / (Time)

Time = T = (Volume) / [(Area of pipe)*(Rate)]

              = (3321200pi)/(1024pi * 2.05)

              = 1582.126524s

4 0
2 years ago
The accompanying data are lengths (inches) of bears. Find the percentile corresponding to 65.5 in.
Jlenok [28]

Complete question is missing, so i have attached it.

Answer:

Percentile is 74th percentile

Step-by-step explanation:

All the lengths given are;

Bear Lengths 36.5 37.5 39.5 40.5 41.5 42.5 43.0 46.0 46.5 46.5 48.5 48.5 48.5 49.5 51.5 52.5 53.0 53.0 54.5 56.8 57.5 58.5 58.5 58.5 59.0 60.5 60.5 61.0 61.0 61.5 62.0 62.5 63.5 63.5 63.5 64.0 64.0 64.5 64.5 65.5 66.5 67.0 67.5 69.0 69.5 70.5 72.0 72.5 72.5 72.5 72.5 73.0 76.0 77.5

The number of lengths (inches) of bears given are 54 in number.

We are looking for the percentile corresponding to 65.5 in.

Looking at the lengths given, since they are already arranged from smallest to highest, let's locate the position of 65.5 in.

The position of 65.5 in is the 40th among 54 lengths given.

If the percentile is P, then;

P% x 54 = 40

P = (40 × 100)/54

P ≈ 74

3 0
2 years ago
Quadrilateral WXYZ is on a coordinate plane. Segment XY is on the line x − 3y = −12, and segment WZ is on the x − 3y = −6. Which
Nostrana [21]

Answer:

Equation shown

Step-by-step explanation:

Eq(1): x-3y=-12

X=-12+3y

=-4+y

Eq(2): x-3y=-6

X=-6+3y

=-2+y

4 0
2 years ago
Read 2 more answers
Suppose the average price for new cars in 2012 has a mean of $30,100 and a standard deviation of $5,600. Based on this informati
KatRina [158]

Answer:

($13,300,$46,900)

Step-by-step explanation:

We are given the following in he question:

Mean, μ = $30,100

Standard Deviation, σ = $5,600

Chebyshev's Theorem:

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  • For k = 3,

1 -\dfrac{1}{(3)^2} = 0.889 \approx 89\%

Thus, 89% of data lies within three standard deviation of mean.

\mu - 3(\sigma) = 30100 - 3(5600) = 13300\\\mu + 3(\sigma) = 30100 + 3(5600) = 46900

Thus, we expect at least 89% of new car prices to fall within ($13,300,$46,900)

3 0
2 years ago
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Minchanka [31]

Answer:

8.899s

Solve: -5t^+40t+40

7 0
2 years ago
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