Cannot see your image, but the formula for the volume of a sphere is
V=(4/3)πr³
to solve for r: r³=v÷(4/3)π=v*3/(4π)=3v/(4π) (three v out of 4 pi)
r=∛(3v/4π)
r equals the cubic root of (three v over 4π)
Answer:
Option A is correct
The expression which is equivalent to
is
Step-by-step explanation:
Using the formula:
.....[1]
Given the expression:

Substitute the value of x = 5 in [1]
we get;
Therefore, the expression which is equivalent to
is
Answer:
The probability mass of X is 0.03
Step-by-step explanation:
If we set the winning requirement of your heads and my tails then the occurring possibility of both is 1/2 or 0.5.
Hence let us make a graph and use the figures to calculate the all the probabilities of you getting a heads.
Where X represents the number of dollars won during the flip of the coin, probability of heads represent the chances of occurrence of the value and of winning the dollars.
The probability of winning start to drop as the winning amount increases.
X 0 1 2 3 4 5
Probability of Heads 0 0.50 0.25 0.13 0.06 0.03
Answer:
AB parallel to CD because both lines have a slope of
of 4/3
Step-by-step explanation:
The question is not complete, there is no graph.
A graph for the question is attached below.
From the image attached below, line 1 passes through points A = (-3, -3) and point B = (0, 1) while line 2 passes through point C = (0, -5) and point D = (3, -1).
Two parallel are said to be parallel if the have the same slope. The slope of a line passing through points:

Line 1 passes through points A = (-3, -3) and point B = (0, 1), the slope of line 1 is:

Line 2 passes through point C = (0, -5) and point D = (3, -1). the slope of line 2 is:

Therefore AB parallel to CD because both lines have a slope of
of 4/3
Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as

where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r