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elena-s [515]
2 years ago
12

The Taylors have recorded their weekly grocery expenses for the past 12 weeks and determined that the mean weekly expense was ​$

.82.55. Later Mrs. Taylor discovered that one​ week's expense of​ $74 was incorrectly recorded as​ $47. What is the correct​ mean?
Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
4 0

Answer:

$84.80

Step-by-step explanation:

find the difference between accurate price and written price: 74 - 47 = 27

find written total (before Mrs. Taylor found mistake) by undoing the mean calculation: 82.55 x 12 = $990.60

the total expenses is $27 more than what they thought: 990.60 + 27 = 1017.60

divide accurate total by 12 to find mean: 1017.60 / 12 = $84.80

hope this helps :)

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A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.
BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to 160\ ft^{2}

Part b) The volume is equal to 240\ ft^{3}

Part c) The volume water left in the trough will be 84\ ft^{3}

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

A=2[12*5]=120\ ft^{2}

<em>Find the area of two trapezoids</em>

A=2[\frac{1}{2}(8+2)h]

Applying Pythagoras theorem calculate the height h

h^{2}=5^{2}-3^{2}

h^{2}=16

h=4\ ft

substitute the value of h to find the area

A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}

The exterior surface area is equal to

120\ ft^{2}+40\ ft^{2}=160\ ft^{2}

Part b) Find the volume

We know that

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=20\ ft^{2}

L=12\ ft

substitute

V=20(12)=240\ ft^{3}

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

A=\frac{1}{2}(5+2)(2)=7\ ft^{2}

<em>step 2</em>

Find the volume

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=7\ ft^{2}

L=12\ ft

substitute

V=7(12)=84\ ft^{3}

4 0
2 years ago
Find the area of segment CFD given the following information: radius = 8in, area of ΔCBD = 25.9in2, and m∠CBD = 54° Round your a
Llana [10]

Answer:

A. 4.26 in^2

Step-by-step explanation:

Step 1: Find the area of the sector DBC. Here we have to use the formula.

Area of a sector = Central Angle/360 *πr^{2}

The area of the sector DBC = (54/360)*3.14*8^{2}

= 30.16

Step 2: Area of segment CFD = Area of the sector DBC - Area of the ΔCBD

= 30.17 - 25.9

Area of segment CFD = 4.27in^2

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Answer:

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la distancia del punto de observación B al incendio = 3.8 millas

Step-by-step explanation:

La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :

Del siguiente diagrama;

Usando la sine regla:

\dfrac{sin \  F}{f} = \dfrac{sin  \ A }{a}

\dfrac{sIn \  79}{6} = \dfrac{sin \   63}{a}

a sin 79 = 6 sin 63

a =\dfrac{6 \times sin \ 63}{sin \ 79}

a =\dfrac{6 \times 0.8910}{0.9816}

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\dfrac{sin \  F}{f} = \dfrac{sin  \ B}{b}

\dfrac{sin \  79}{6} = \dfrac{sin  \ 38}{b}

b sin 79 = 6 sin 38

b  = \dfrac{6 \times sin  \ 38}{sin \  79}

b  = \dfrac{6 \times0.6157 }{0.9816}

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Move the decimal back to its point of origin

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Masteriza [31]

Answer:

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Step-by-step explanation:

Lake Superior is by far the largest and deepest of the great Lakes. Lake Michigan is exceeded in depth only by Lake Superior, but it is exceeded in area by both Lakes Superior and Huron. Lake Ontario, which is the smallest in area, is deeper than both Lakes Huron and Erie. Lake Erie is larger than Lake Ontario but it is not only shallower than Huron; it is also shallower than Ontario. So, the order of Great Lakes according to depth is (descending order): 1. Lake Superior 2. Lake Michigan 3.  Lake Ontario 4. Lake Huron 5. Lake Erie

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