<h3><u>Radius as function of volume is:</u></h3>

<em><u>Solution:</u></em>
<em><u>The volume of cone is given as</u></em>:

Where,
r is the radius
h is the height
From given,
height = 20 inches
From formula,

Rearrange , so that r is alone in left side of equation

Substitute h = 20

Thus, radius as function of volume is:

Answer:
Option C is correct
Step-by-step explanation:
Given: vertex of this parabola is at (-2,-3)
To find: coefficient of the squared expression in the parabola’s equation if the x-value is -1, the y-value is -5
Solution:
The equation of parabola is of the form 
Here, a is the coefficient of the squared expression in the parabola’s equation.
Put 

So, the coefficient of the squared expression in the parabola’s equation is 
Given the conditional relative frequency table below which was generated by
column using frequency table data comparing the number of calories in a meal to
whether the meal was prepared at home or at a restaurant.
Number of Calories and Location of Meal Preparation.
Home Restaurant Total
≥ 500 calories 0.15 0.55 0.28
< 500 calories 0.85 0.45 0.72
Total 1.0 1.0 1.0
To determine whether there is an association between where food is prepared and the number of carories the food contain, we recall that an "association" exists between two categorical variables if the column conditional relative frequencies are different
for the columns of the table. The bigger the differences in
the conditional relative frequencies, the stronger the association
between the variables. If the conditional relative frequencies are
nearly equal for all categories, there may be no association between the
variables. Such variables are said to be <span>independent.
For the given conditional relative freduency, we can see that there is a significant difference between the columns of the table.
i.e. 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45
Therefore, we can conclude from the given answer options that t</span><span>here is an association because the value 0.15 is not similar to the value 0.55</span>
Answer:
Step-by-step explanation:
Rate of leakage, R(t) = 1400 e^0.06t gallons/h
fraction remains , S(t) = e^(-0.32t)
initial contaminant = 1000 gallon
gallons contaminant present after t hour is S(t) R(t)
G(t) = S(t) R(t)


Put t = 18 hours

Taking log on both the sides
ln G = ln 1400 - 0.26 x 18
ln G = 7.244 - 4.68
ln G = 2.564
G = 13 gallons