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Zepler [3.9K]
2 years ago
7

Assume that z scores are normally distributed with a mean of 0 and a standard deviation of 1. if p(z >

Mathematics
1 answer:
madreJ [45]2 years ago
8 0
Given that μ=0, and σ=1, P(z>c)=0.1093
thus
P(z<c)=1-0.1093=0.8907
hence the value of c will be:
z-score=(c-μ)/σ
thus
1.23=(c-0)/1
c=1.23
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