Question

Assume that z scores are normally distributed with a mean of 0 and a standard deviation of 1. if p(z >

Answer 1

Given that μ=0, and σ=1, P(z>c)=0.1093
thus
P(z<c)=1-0.1093=0.8907
hence the value of c will be:
z-score=(c-μ)/σ
thus
1.23=(c-0)/1
c=1.23