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Alexeev081 [22]
2 years ago
10

The system of equations y = one-fourth x minus 1 and y = negative one-half x minus one-fourth is shown on the graph below. On a

coordinate plane, 2 lines intersect at (1, negative three-fourths). What is a reasonable estimate for the solution? (1, negative three-fourths) (Negative three-fourths, 1) (Negative 1, three-fourths) (Three-fourths, negative 1)
Mathematics
2 answers:
love history [14]2 years ago
8 0

Step-by-step explanation:

<u>Step 1:  Convert into expressions</u>

y = one-fourth x minus 1 → y = \frac{1}{4}x-1

y = negative one-half x minus one-fourth → y = -\frac{1}{2}x - \frac{1}{4}

They intersect at (1, -\frac{3}{4})

Answer: Option A, (1, negative three-fourths)

skad [1K]2 years ago
5 0

Answer:

First one: (1,-¾)

Step-by-step explanation:

y = ¼x - 1

y = -½x - ¼

¼x - 1 = -½x - ¼

¾x = ¾

x = 1

y = ¼ - 1 = -¾

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Under ideal conditions a certain bacteria population is known to double every three hours. Suppose that there are initially 100
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the estimation of the size of the population after 20 hours is 10159

Step-by-step explanation:

The computation of the size of the population after 20, hours is shown below;

= 100  2^(20 by 3)

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If we divide 20 by 3 so it would give 6.66 that lies between 6 and 7

So the estimation of the size of the population after 20 hours is 10159

hence, the same is relevant

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2 years ago
TU = 3, RS = 15, TW = 4, TR = 9; Assume that the sides of triangle TUW are proportional to the sides of triangle TRS. What is th
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Answer:

  WS=8\ units

Step-by-step explanation:

we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal and the corresponding angles are also equal

In this problem

\frac{TU}{TR}=\frac{UW}{RS}=\frac{TW}{TS}

we have

TU=3\ units, RS=15\ units, TW=4\ units,TR=9\ units

Find the value of TS

\frac{TU}{TR}=\frac{TW}{TS}

substitute

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TS=36/3=12\ units

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WS=12-4=8\ units

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2 years ago
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A sample of the salaries of assistant professors on the business faculty at a local university revealed a mean income of $100,00
serg [7]

Answer:

a) 68%

b) 95%.

c) 2.5%

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 100,000, standard deviation of 10,000.

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90,000 = 100,000 - 10,000

110,000 = 100,000 + 10,000

Within 1 standard deviation of the mean, so approximately 68%.

b. Approximately what percentage of the salaries fall between $80,000 and $120,000?

80,000 = 100,000 - 2*10,000

120,000 = 100,000 + 2*10,000

Within 2 standard deviations of the mean, so approximately 95%.

c. Approximately what percentage of the salaries are greater than $120,000?

More than 2 standard deviations above the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean, so approximately 5% are more than 2 standard deviations from the mean.

The normal distribution is symmetric, which means that 2.5% are more then 2 standard deviations below the mean, and 2.5% are more than 2 standard deviations above the mean, which means that 2.5% of the salaries are greater than $120,000.

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