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Alexeev081 [22]
1 year ago
10

The system of equations y = one-fourth x minus 1 and y = negative one-half x minus one-fourth is shown on the graph below. On a

coordinate plane, 2 lines intersect at (1, negative three-fourths). What is a reasonable estimate for the solution? (1, negative three-fourths) (Negative three-fourths, 1) (Negative 1, three-fourths) (Three-fourths, negative 1)
Mathematics
2 answers:
love history [14]1 year ago
8 0

Step-by-step explanation:

<u>Step 1:  Convert into expressions</u>

y = one-fourth x minus 1 → y = \frac{1}{4}x-1

y = negative one-half x minus one-fourth → y = -\frac{1}{2}x - \frac{1}{4}

They intersect at (1, -\frac{3}{4})

Answer: Option A, (1, negative three-fourths)

skad [1K]1 year ago
5 0

Answer:

First one: (1,-¾)

Step-by-step explanation:

y = ¼x - 1

y = -½x - ¼

¼x - 1 = -½x - ¼

¾x = ¾

x = 1

y = ¼ - 1 = -¾

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2 years ago
What are the solution(s) to the quadratic equation 40 − x2 = 0?
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4 0
2 years ago
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A rectangular container can hold 45 candles, while a cylindrical container holds 41 candles. Each rectangular container costs th
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Answer: Rectangular container is preferred to minimize the costs and  there are 142 rectangular container is needed to pack 6400 candles.

Explanation:

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Number of candles in a rectangular container = 45

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Cost of each rectangular container = $15

Cost of each cylinder container = $16

That means ,

In case of rectangular container,

Cost of 45 candles = $15

Cost of 1 candle is given by

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In case of cylindrical container,

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Cost of 1 candle is given by

\frac{16}{41}=\$0.39

So, if the company needs to package 6,400 candles , it should use <u>rectangular containers </u>to minimize costs.

Number of candle he need to pack = 6400

Number of rectangular container for 6400 candles is given by

\frac{6400}{45}=142.2=142\ approximately.

Hence, there are 142 rectangular container is needed to pack 6400 candles.


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2 years ago
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  B. 10 months

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The balance on the loan will be ...

  b = 1600 - 80t . . . . . . where t is the number of months of payments

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  s = 500 + 25t

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  s ≥ b

  500 +25t ≥ 1600 -80t . . . substitute the account balance expressions

  105t ≥ 1100 . . . . . . . . . . . . add 80t -500

  t ≥ 1100/105 ≈ 10.48 ≈ 10

It will take Josh 10 months to have enough savings to pay the loan in full.

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<em>Comment on rounding</em>

IMO, it makes no sense to round down, as Josh will NOT have enough in 10 months. He will have enough after he makes one more payment of $80. At 10 months, the loan balance is $50 more than the savings balance. It will be 11 months before there is enough savings to pay off the loan.

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