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NISA [10]
2 years ago
10

A rectangular container can hold 45 candles, while a cylindrical container holds 41 candles. Each rectangular container costs th

e company $16, while the cylindrical container costs the company $15. If the company needs to package 6,400 candles, should it use only rectangular or only cylindrical containers to minimize costs? Explain. How many rectangular containers will be necessary to package 6,400 candles?
Mathematics
2 answers:
VikaD [51]2 years ago
5 0

Answer:

143 ... 157 ... the rectangular containers, because it will cost the company $67 more to use the cylindrical containers

I just did the assignment, and those were the correct answers.


Delvig [45]2 years ago
4 0

Answer: Rectangular container is preferred to minimize the costs and  there are 142 rectangular container is needed to pack 6400 candles.

Explanation:

Since we have given that

Number of candles in a rectangular container = 45

Number of candles in a cylindrical container = 41

Cost of each rectangular container = $15

Cost of each cylinder container = $16

That means ,

In case of rectangular container,

Cost of 45 candles = $15

Cost of 1 candle is given by

\frac{15}{45}=\frac{1}{3}=\$0.33

Similarly,

In case of cylindrical container,

Cost of 41 candles = $16

Cost of 1 candle is given by

\frac{16}{41}=\$0.39

So, if the company needs to package 6,400 candles , it should use <u>rectangular containers </u>to minimize costs.

Number of candle he need to pack = 6400

Number of rectangular container for 6400 candles is given by

\frac{6400}{45}=142.2=142\ approximately.

Hence, there are 142 rectangular container is needed to pack 6400 candles.


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Answer:

Step-by-step explanation:

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3 0
1 year ago
What is the ratio of the area of sector ABC to the area of sector DBE?
shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.


180°= π rad

1° = π/180 rad


For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

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= 3/2 r²(π/180 β)

Now ratio,

Area of sector ABC/Area of sector DBE =\frac{2r^{2}*\ \frac{\pi}{180} beta}{3/2 r^{2}*\ \frac{\pi}{180}beta}

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7 0
2 years ago
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points P and Q lie 240 m apart in line with and on opposite sides of a communications tower. the angles of elevation to the top
Leona [35]

Answer:

The height of the tower is 130.5m

Step-by-step explanation:

In the question, we are given the following values:

The angles of elevation to the top of the tower from P = 50°

The angles of elevation to the top of the tower from Q = 45°

The angles of elevation to the top of the tower from P = 50°

Hence,cot P = 1/ tan(50°)

The angles of elevation to the top of the tower from Q = 45°

Hence, tan 45° = 1

In the question,we are told Points P and Q lie 240 m apart in line with and on opposite sides of a communications tower.

Therefore,

PQ = height of the tower( tan Q + 1/tan P)

240m = height of the tower( tan 45° + 1/ tan 50°)

240m = h(1 + 1/tan 50°)

h = (240 m)/(1 + 1/tan (50°))

h = 130.49863962 meters

Therefore, the height of the tower to the nearest tenth of a meter is 130.5 meters(m)

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2 years ago
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Nastasia [14]

Answer:

A) 8

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Add angles AOB and BOC to get angle AOC.

Since we know the value of AOC is 124 and AOB+BOC=AO

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Combine like terms to get 14x+12= 124.

Solve for x by subtracting 12 from 124, then divide the answer by 14.

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Answer:

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