Given ΔACD and ΔABE, what is AB?

H(y) models the leading number of home runs for season y on the National League between the years 2000-2010, according to the ta

alexandr1967 [171]

Answer:

Integers

2000 $\leq$ x $\leq$ 2010

Step-by-step explanation:

3 0

2 years ago

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A park has a 333 meter (\text{m})(m)left parenthesis, start text, m, end text, right parenthesis tall tether ball pole and a 6.8

dybincka [34]

Answer:option B & D are correct

Step-by-step explanation:

Given options are

A B C D E

Tether ball pole shadow 1.35 1.8 3.75 0.6 2

Flagpole shadow 3.4 4.08 8.35 1.36 4.8

Ratio of corresponding height & shadows should be same

3 meter tall tether ball pole and a 6.8 tall flagpole

=> Ratio = 6.8/3 = 68/30 = 34/15

A - 3.4/1.35 = 340/135 ≠ 34/15( 306/135)

B - 4.08/1.8 = 408/180 = 34/15 = 34/15 ( Correct option)

C 8.35/3.75 = 835/375 = 167/75 ≠ 34/15( 170/75)

D 1.36/0.6 = 136/60 = 34/15 = 34/15 ( Correct option)

E 4.8/2 = 48/20 = 12/5 = 36/15 ≠ 34/15

option B & D are correct

6 0

2 years ago

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PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi

Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

$Hypotenuse^2=Base^2+Perpendicular^2$

⇒ $5^2=3^2+4^2$

Let a, b, c forms a Pythagorean triplet

$a^2+b^2=c^2$

Multiplied by 4 on both sides

⇒ $4a^2+4b^2=4c^2$

⇒ ${2a}^2+{2b}^2={2c}^2$

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

4 0

2 years ago

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Leah decided to paint some of the rooms at her 51-room hotel. She needs 1/5 of a can of paint per room. If Leah had 6 cans of pa

netineya [11]

Answer:

Leah can paint 30 rooms.

Step-by-step explanation:

Each room requires $\dfrac{1}{5}$ of a can of paint, this means painting 5 rooms requires

$\dfrac{1}{5}+\dfrac{1}{5}+\dfrac{1}{5}+\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{1+1+1+1+1}{5}=\dfrac{5}{5} =1$

or 1 can paints 5 rooms.

So, if Leah has 6 cans of paint, then how many rooms can she paint?

Leah can paint

$\dfrac{5\:rooms}{can} *6\:cans=\boxed{30\: rooms}$

Leah can paint 30 rooms with 6 cans of paint.

5 0

2 years ago

Evaluate. 58−(14)2=58-142= ________

nasty-shy [4]

For this case we have the following expression:

$58- (14) ^ 2$

The first step is to solve the quadratic term.

We have then:

$58- (14) ^ 2 = 58-196$

Then, the second step is to subtract both resulting numbers:

$58- (14) ^ 2 = -138$

We observe that the result obtained is a negative number.

Answer:

The result of the expression is given by:

$58- (14) ^ 2 = -138$

7 0

2 years ago