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Ilia_Sergeevich [38]

2 years ago

11

Olivia and ray walk to school. olivia walks 1\4 of a mile to school. her walks is 2\3 of the distance that ray walks to school.

waht is the total distance, in miles that ray walks to school? answer

1 answer:

Pepsi [2]2 years ago

8 0

We know that

<span>Olivia walks ---------> 1\4 of a mile to school
</span>
2/3 correspond to ------> 0.6666------> 66.67 %
3/3 correspond to--------> 1--------> 100%
so
if (2/3)-----------> 1/4 mile
(3/3)-------------> x
x=(1/4)/(2/3)-----> x=(1/4)*3/2-----> x=3/8------> x-0.375 miles

the answer is
<span>Ray walks to school 3/8 miles (0.375 miles)</span>

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Answer:

$229673.215

Step-by-step explanation:

Given : The price of attending Big Benefits University is $42,000 a year, including tuition, fees, books, and foregone earnings

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Solution:

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Time = 5 years

Rate = 3% = 0.03

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$A_2=42000(1+0.03)^2$

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$A_4=42000(1+0.03)^4$

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5 0

1 year ago

If pq=9 and qr=28, find PR

Ksenya-84 [330]

PQ = 9
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9 + 28 = PR

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hope this helps

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2 years ago

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stealth61 [152]

Note that

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In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

b

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

c

The probability, $P =0.0002$

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

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substituting the value

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The standard deviation is mathematically represented as

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substituting the value

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$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

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Lera25 [3.4K]

Answer:

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