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otez555 [7]
1 year ago
15

The signs show the costs of different games at a math festival. How much would it cost n people to play Decimal Decisions and Ra

tio Rage?

Mathematics
1 answer:
Oduvanchick [21]1 year ago
7 0

Answer:

$(21.70 - \frac{3n}{4})

Step-by-step explanation:

See the sign attached to the question.

The sign shows the costs of different games at a math festival.

The Decimal Decision game costs $(12.70 - n + 9) for n people to play.

And, The Ratio Rage game costs $\frac{n}{4} for n peoples to play.

Therefore, it will cost $(21.70 - n + \frac{n}{4}) = (21.70 - \frac{3n}{4}) Dollars. (Answer)

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Two fish are put in a man-made lake with no other fish in it. Each month, the fish population triples. Which model and equation
aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

The basic model for this growth is the exponential function:  y = a(b)^c, where a is the initial value, b is the growth rate and c is the time.

Here we have P = fish population = (2 fish)(3)^t

8 0
2 years ago
The list shows the area in square feet of each apartment available for rent in a building. 565, 961, 867, 517, 627, 714, 517, 72
gladu [14]
STEP 1:
put numbers in order from lowest to highest
517, 517, 565, 627, 714, 728, 867, 961

STEP 2:
find the difference between the lowest and highest numbers

961 - 517= 444 ft^2 range

ANSWER: The range of the areas is 444 ft^2.

Hope this helps! :)
8 0
2 years ago
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Which statements are true regarding the regular dodecagon? Check all that apply.
ladessa [460]
A dodecagon has 12 sides.  That means that the smallest angle of rotational symmetry is 360/12 or 30°.  All of its angles of rotational symmetry will be multiples of 30, including 180°.  135°, since it is not a multiple of 30°, is not a rotational angle for this figure.  The order of °rotational symmetry is 12, as there are 12 sides you can turn this figure to (since it is regular).
6 0
2 years ago
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A bridge is rated to a capacity of 100 British tons. What is the maximum weight the bridge can support in kilograms? (Round to t
S_A_V [24]

Maximum weight the bridge can support in kilograms is 101696

Step-by-step explanation:

  • Step 1: Given capacity of bridge = 100 British tons. Find how many kilograms are equivalent to 1 British ton.

1 British ton = 2240 pounds

1 pound = 0.454 kg

⇒ 1 British ton = 2240 × 0.454 kg = 1016.96 kg

  • Step 2: Find how many kilograms are in 100 British tons.

⇒ 100 × 1016.96 = 101696

3 0
2 years ago
n 2019, approximately 97.4% of all the runners who started the Boston Marathon (in Boston, Massachusetts, USA) were able to comp
Zarrin [17]

Answer:

0.1199 = 11.99% probability that at least 5 of them did not finish the marathon

Step-by-step explanation:

For each runner, there are only two possible outcomes. Either they finished the marathon, or they did not. The probability of a runner completing the marathon is independent of any other runner. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

97.4% finished:

This means that 100 - 97.4 = 2.6% = 0.026 did not finish, which means that p = 0.026

100 runners are chosen at random

This means that n = 100

Find the probability that at least 5 of them did not finish the marathon

This is:

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.026)^{0}.(0.974)^{100} = 0.0718

P(X = 1) = C_{100,1}.(0.026)^{1}.(0.974)^{99} = 0.1916

P(X = 2) = C_{100,2}.(0.026)^{2}.(0.974)^{98} = 0.2531

P(X = 3) = C_{100,3}.(0.026)^{3}.(0.974)^{97} = 0.2207

P(X = 4) = C_{100,4}.(0.026)^{4}.(0.974)^{96} = 0.1429

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0718 + 0.1916 + 0.2531 + 0.2207 + 0.1429 = 0.8801

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.8801 = 0.1199

0.1199 = 11.99% probability that at least 5 of them did not finish the marathon

4 0
1 year ago
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