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otez555 [7]
1 year ago
15

The signs show the costs of different games at a math festival. How much would it cost n people to play Decimal Decisions and Ra

tio Rage?

Mathematics
1 answer:
Oduvanchick [21]1 year ago
7 0

Answer:

$(21.70 - \frac{3n}{4})

Step-by-step explanation:

See the sign attached to the question.

The sign shows the costs of different games at a math festival.

The Decimal Decision game costs $(12.70 - n + 9) for n people to play.

And, The Ratio Rage game costs $\frac{n}{4} for n peoples to play.

Therefore, it will cost $(21.70 - n + \frac{n}{4}) = (21.70 - \frac{3n}{4}) Dollars. (Answer)

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Answer:

0.1/4-3/20=1/40-6/40=-1/8 200% of this is -1/4

Step-by-step explanation:

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Identify the segment bisector of JK
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Answer:

A segment whose length is 9 units.

Step-by-step explanation:

A segment whose length is 9 units.

All we have is a bisection that divides equally segment JK in two parts. And M is the Midpoint what reassures us that JM=MK, so plugging in:

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2 years ago
If four is half of five and two thirds of six is nine. what is thirty-two?
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