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SOVA2 [1]
2 years ago
12

Roger and rita each drive at a constant speed between phoenix and san diego. Each driver’s distance for the same section of the

trip is displayed below. Who had a head start
Mathematics
2 answers:
pickupchik [31]2 years ago
7 0

Answer:

the answer is A

Step-by-step explanation:

ITS ON EDGE

never [62]2 years ago
5 0

Answer:

a)Rita had a 28-mile head start

Step-by-step explanation:

The multiple options have been added in the additional information below the problem statement.

<u>Missing Information:</u>

Since the distance of each driver is not displayed. Let us assume their distances.

Say,

Roger travelled distance = 60 miles

Rita travelled distance = 32 miles

Now as it is given in the problem statement that Roger and Rita both drove at a constant speed between Phoenix and San Diego and they drove "Same Section of the trip" .

Which Means that the distance travelled of both is between Phoenix and San Diego, just their starting points are different but their end point is the same which is San Diego.

<em><u>As we can see RIta had to cover less miles which means she got the head start, now to calculate how much of a head start she got, we need:</u></em>

Head Start Rita got = Distance Roger travelled - Distance Rita Travelled

Head Start Rita got = 60 - 32 = 28 miles

So,

Rita got a Head start of 28 miles which is option (a)

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In ΔKLM, m = 59 cm, ∠L=111° and ∠M=60°. Find the length of l, to the nearest centimeter.
g100num [7]

Answer:

64 (or 63.6)

Step-by-step explanation:

You can figure out the <K by adding the first two angles (111+60) and getting 171 (subtracting that from 180 gives you a 9-degree angle for <K

Given three angles and 1 side, you can calculate the sides as follows:

k=m*sin (K) / sin (M) = 10.65

l=m*sin (L) / sin (M) = 63.60234

Since you're solving for l, the steps would be:

l=59 * sin (111) / sin (60)

l=59 * (0.934) / (0.866)

l=55.106 / 0.866

l=63.63

Hope this helps!

4 0
2 years ago
The line plot shows the number of hours students studied for a final exam. A number line with one x above .5, one x above 1.5, o
saw5 [17]
To read the line plot in order to answer this question, you will need to understand that each X above the numbers represents the number of hours 1 student studied. If you count the total number of Xs, that would represent the total number of students surveyed.

The number of students that studied at least four hours, would be the number of Xs that are at 4 or above. This means there were 4 students that studied for hours or more.
5 0
2 years ago
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Which expressions are equivalent to 7^{-2}\cdot 7^67
AleksandrR [38]

Answer:

{7}^{ - 2}   \cdot \:  {7}^{6}  =  {7}^{ 4}

Step-by-step explanation:

The given expresion is;

{7}^{ - 2}  \cdot {7}^{6}

We apply the product rule of indices;

{a}^{m}   \cdot \:  {a}^{n}  =  {a}^{m + n}

We apply this property to our expression to get:

{7}^{ - 2}   \cdot \:  {7}^{6}  =  {7}^{ - 2 + 6}

Simplify the exponent on the right;

{7}^{ - 2}   \cdot \:  {7}^{6}  =  {7}^{ 4}

We can't see the options, but I hope this helps!

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2 years ago
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Inessa05 [86]
Year      Net Profit
1            <span>$14,250.00
2            $15,390.00
3            $16,621.20
4            $17,950.90</span>2

We need to get the increase of the net profit of the current year from the previous year.

Percentage increase = (Current year - Previous Year)/ Previous Year    * 100%

Year 2:  (15,390 - 14, 250) / 14,250   * 100% = 0.08 * 100% = 8%
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Every year the net income increases by 8%. So, the net income in Year 5 will be:

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8 0
2 years ago
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Which statement identifies how to show that j(x) = 11.6ex and k(x) = In (StartFraction x Over 11.6 EndFraction) are inverse func
Vadim26 [7]

Answer:

<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>

Step-by-step explanation:

Given the function  j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6}, to show that both equality functions are true, all we need to show is that both  j(k(x)) and k(j(x)) equal x,

For j(k(x));

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j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}

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j[(ln x/11.6)] = x

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Similarly for k[j(x)];

k[j(x)] = k[11.6e^x]

k[11.6e^x] = ln (11.6e^x/11.6)

k[11.6e^x]  = ln(e^x)

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k[11.6e^x]  = x

Hence k[j(x)] = x

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4 0
2 years ago
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