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ICE Princess25 [194]
2 years ago
7

A scatterplot is produced to compare the number of hours that students study to their test scores. There are 25 data points, eac

h representing a different student. The scatterplot shows a grouping of points rising from left to right. Which statement could be true?
a.)There is no relationship between the number of hours that students study and their test scores because the scatterplot does not have a cluster.
b.)As the number of hours of studying increases, test scores decrease because the scatterplot has a cluster that increases from left to right.
c.)As the number of hours of studying increases, test scores increase because the scatterplot has a cluster that increases from left to right.
d.)The number of hours that students study is equal to the test scores because the scatterplot does not show a cluster.
Mathematics
2 answers:
Airida [17]2 years ago
5 0
The answer would be C) As the number of hours of studying increases, test scores increase because the scatterplot has a cluster that increases from left to right.

Any questions? Ask me in the comments bellow.
Hope this helps. :)
Harman [31]2 years ago
3 0

Answer:

c

Step-by-step explanation:

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Answer:

The vertical asymptotes are x = 2 and x =  -2.

The horizontal asymptote is y = 3.

Step-by-step explanation:

Given the function

f(x)=\dfrac{3x^2}{x^2-4}

Rewrite it as follows:

f(x)\\ \\=\dfrac{3x^2}{x^2-4}\\ \\=3\dfrac{x^2-4+4}{x^2-4}\\ \\=3\left(1+\dfrac{4}{x^2-4}\right)\\ \\=3+\dfrac{12}{(x-2)(x+2)}

This function is undefined when the denominator is equal to 0. The denominator is equal to 0 when x = 2 or x = -2, so two vertical asymptotes are x = 2 and x =  -2.

The horizontal asymptote is y = 3.

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Answer:

a) 0.32

b) 0.68

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P(B) =P(adult)+P(child)+P(other)\\P(B) = 0.03+0.15+0.14\\P(B) =0.32

b) The probability that a PC is not in a bedroom is 100% minus the probability of it being in a bedroom:

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c) The expected room to find a PC from a randomly selected household is the room with highest likelihood of having a PC according to Consumer Digest. The Office or den, is the most probable room with a 0.40 chance.

You would expect to find a PC in the Office or den.

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2 years ago
A major department store has determined that its customers charge an average of $500 per month, with a standard deviation of $80
julia-pushkina [17]

Answer:

Step-by-step explanation:

Since the amounts of charges are assumed to be normally distributed,

we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = the amounts of charges.

µ = mean amount

σ = standard deviation

From the information given,

µ = $500

σ = $80

a) the probability that customers charges more than $380 per month is expressed as

P(x > 380) = 1 - P(x ≤ 380)

For x = 380,

z = (380 - 500)/80 = - 1.5

Looking at the normal distribution table, the probability corresponding to the z score is 0.067

P(x > 380) = 1 - 0.067 = 0.933

The percentage of customers that charges more than $380 per month is

0.933 × 100 = 93.3%

b) the probability that customers charges less than $340 per month is expressed as

P(x < 340)

For x = 340,

z = (340 - 500)/80 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.023

The percentage of customers that charges less than $340 per month is

0.023 × 100 = 2.3%

c) the probability that customers charges between $644 and $700 per month is expressed as

P(644 ≤ x ≤ 700)

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z = (644 - 500)/80 = 1.8

Looking at the normal distribution table, the probability corresponding to the z score is 0.96

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z = (700 - 500)/80 = 2.5

Looking at the normal distribution table, the probability corresponding to the z score is 0.994

P(644 ≤ x ≤ 700) = 0.994 - 0.96 = 0.034

The percentage of customers that charges between $644 and $700 per month is

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Answer:  The correct option is

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So, options (B), (C), (D) and (E) are not correct because they contradict conditions of similarity.

In option (A), we have

The measures of corresponding angles of ABCD and KLMN are equal. So, they must be congruent.

And the lengths of corresponding sides of ABCD are half those of KLMN.

So, we can write

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mihalych1998 [28]
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8 0
2 years ago
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