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Liono4ka [1.6K]
2 years ago
10

A recipe that makes 4 servings calls for Two-thirds cup of flour. How much flour is required to make 20 servings? 6 cups 3 and o

ne-third cups two-thirds cups StartFraction 2 over 15 EndFraction cups
Mathematics
2 answers:
Vlad [161]2 years ago
6 0

Answer:

3 1/3 cups of flour

Step-by-step explanation:

20/4 = 5

20 servings is 5 times 4 servings, so you need 5 times the amount of ingredients.

5 * 2/3 = 10/3 = 3 1/3

Answer: 3 1/3 cups of flour

Verizon [17]2 years ago
4 0

Answer:

3 1/3 cups of flour is your answer.

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Lelia says that 75% of a number will always be greater than 50% of a number. Complete the inequality to support Lelia's claim an
worty [1.4K]

Answer:

Let 'x' and 'y' be two different numbers.

Leila says that 75% of a number will always be greater than 50% of a number. The inequality that represents this statement is the following:

0.75x > 0.5y

Let x = 100 and y=200. We have that:

0.75(100) > 0.5(200)

75 > 100 ❌ INCORRECT ❌

Given that we found a case in which 75% of a number is not greater than 50% of a number, we can conclude that Leila's claim is incorrect.

3 0
2 years ago
A student rolled two six-sided dice 100 times. The table captures the total of the dice on each roll. How to show results using
ivann1987 [24]
I think the best way to show the results in a chart format is to put zero to twelve on the y-axis or vertically and zero to one hundred on the x-axis or horizontally. Label the y-axis total per roll and the x-axis roll number.Then plot the coordinates or pairs from the table.
5 0
2 years ago
Read 2 more answers
Consider the following problem: A farmer with 950 ft of fencing wants to enclose a rectangular area and then divide it into four
Alina [70]

Answer:

Step-by-step explanation:

(a)

Suppose we came up with an ideology whereby we pick a value for the length including the length dividing the inside into 4 parts(5 parallel sides), then we can get the value for breath by using the following process.

Let assume the length of the rectangle is 50;

Then, the breath can be calculated as follows:

= 50 × 5 = 250   ( since the breath is divided into 5 parallel sides)

The fencing is said to be 950 ft

So, 950 - 250 = 700

Then divided by 2, we get:

= 700/2

= 350

So for the first diagram; the length = 50 and the breath = 350

The area = 50 × 350 = 17500 ft²

Now, let's go up a little bit.

If the length increase to 100;

Then 100 × 5 = 500

⇒ 950 - 500 = 450

⇒ 450/2 = 225

The area = 225 × 100 = 22500 ft²

Suppose the length increases to 150

Then 150 × 5 = 750

⇒ 950 - 750 = 200

⇒ 200/2 = 100

The area = 150 × 100 = 15000 ft²

The diagrams for each of the outline above can be seen in the image attached below.

(b) The diagram illustrating the general solution can be seen in the second image provided below.

(c) The expression for  the total area A in terms of both x and y is:

Area A = x×y

(d) Recall that:

The fencing is said to be 950 ft.

And the length is divided inside into 5 parallel sides;

Then:

5x + 2y = 950  (from the illustration in the second image below)

2y  = 950 - 5x

y = \dfrac{950}{2} - \dfrac{5}{2}x

y = 475- \dfrac{5}{2}x

(e)

From (c); replace the value of y in (d) into (c)

Then:

Area A = x×y

f(x)= x\times ( 475 -\dfrac{5}{2}x)

Open brackets

f(x)= ( 475 x-\dfrac{5}{2}x^2)

(f)

By differentiating what we have in (e)

f(x)= ( 475 x-\dfrac{5}{2}x^2)

f'(x)= ( 475 (1)-\dfrac{5}{2}(2x))

f'(x)= 475 -5x

\implies  475 = 5x

x = 475/5

x = 95

From (d):

y = 475- \dfrac{5}{2}x

y = 475- \dfrac{5}{2}(95)

y =237.5

∴

Area A = x × y

Area A = 95 × 237.5

Area A = 22562.5 ft²

5 0
2 years ago
Divide 6K2 - 15k-5 by 3k​
icang [17]

Answer:

Step-by-step explanation:

6k^2

------- = 2k; and:

 3k

-15k

------- = -5

 3k

-5 cannot be evenly divided by 3k, so there's a remainder instead.

6k^2 - 15k - 5

-------------------- = 2k -5 with remainder -5.

         3k

4 0
2 years ago
Read 2 more answers
Part A: During what interval(s) of the domain is the water balloon's height increasing?
Advocard [28]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A: During what interval(s) of the domain is the water balloon's height increasing?

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet

Part B: During what interval(s) of the domain is the water balloon's height staying the same?

Between 2 and 4 seconds, the height remains the same at 75 feet. Also from 10 seconds the height of the balloon is at 0 feet

Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest?

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet (i.e. -17.5 ft/s)

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet (i.e. -10 ft/s)

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet (i.e. -10 ft/s)

Hence it decreases fastest from 4 to 6 seconds

Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds

From 10 seconds, the balloon is at the ground, so it remains at the ground (0 feet) even at 16 seconds

6 0
2 years ago
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