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nikklg [1K]
2 years ago
7

A math teacher randomly selects one student in a class to write a probability question on a chalkboard. The teacher then randoml

y selects a different student to answer the probability question. There are 12 boys in the class, and the ratio of boys to girls is 2:3. Find the probability that the teacher selects a girl first and a girl second. Write your answer as a decimal rounded to the nearest thousandth.
Mathematics
2 answers:
Elena L [17]2 years ago
4 0
The Probability that she does is 51/145 or 35%. I hope i am right and was able to help.
jekas [21]2 years ago
4 0

Answer:

The probability that the teacher selects a girl first and a girl second is 0.352

Step-by-step explanation:

Number of boys in class = 12

let number of boys in class = 2x

number of girls in class = 3x

According to the question,

2x = 12

x = 6

So, number of girls = 3x = 3 × 6 = 18

Total number of students = 18 + 12 = 30

Probabiltiy=\frac{Number\:of\:favorable\:outcome}{Number\:of\:Total\:outcome}

Probability of selecting a girl first and second girl = \frac{18}{30}\times\frac{17}{29}

=\frac{51}{145}=0.352\:(nearest\:thousandth)

Therefore, The probability that the teacher selects a girl first and a girl second is 0.352

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Select all that apply. To decide if 12.5 centimeters is greater than 140 millimeters, the first step is to set up a proportion.
Oksi-84 [34.3K]

Answer:

Hey there!

We can't compare two measurements without converting them to  the same units. Thus, we use proportions to make all the values into the same unit.

12.5 cm(\frac{10 milimeters}{1 centimeter}), which converts to centimetres to millimetres.

12.5 cm=125 mm.

Now, we can compare the values of 125 mm and 140 mm.

Clearly, we see that 140 mm is greater than 125 mm.

Let me know if this helps :)

3 0
2 years ago
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A duck's mass at birth was 0.05 kilogram. The duck gained approximately 0.042 kilogram each week. After how many weeks is the du
Alex_Xolod [135]
Given that the first mass of the duck is 0.05 kg and it gains weight at a rate of 0.042 kg/week, the equation that would represent this scenario is,
                               y = 0.05 + 0.042x
where y is weight and x is the number of weeks. To determine the number of weeks in which the duck's mass becomes 0.890,   
                            0.890 = 0.05 + 0.042x
The value of x from the equation is 20. 
4 0
2 years ago
A company purchased a delivery van for $28,000 with a salvage value of $3,000 on September 1, Year 1. It has an estimated useful
Tems11 [23]

Answer:

Depreciation till December 31, Year 1 will be equal to 1,250$

Step-by-step explanation:

Purchasing Cost = 28,000$

Salvage Value = 3,000$

Total Depreciation:

Total Depreciation over 5 years (60 Months) = Purchasing Cost - Salvage Value

Total Depreciation over 5 years (60 Months) = 28,000 - 3,000

Total Depreciation over 5 years (60 Months) = 25,000$

Monthly Depreciation:

Using the unity method we have monthly depreciation by dividing the total depreciation by the total no. of months as below:

Total Depreciation over a single month =25,000/60

Total Depreciation over a single month = 416.67$ (Monthly Depreciation)

Depreciation till December 31, Year 1

As from September 1, Year 1 to December 31, Year 1, its been 3 months therefore total depreciation will be = 3 * Monthly Depreciation

Depreciation till December 31, Year 1 = 3 * 416.67

Depreciation till December 31, Year 1 = 1,250$

4 0
2 years ago
Consider the system of linear equations. 5x+10y=15 10x+3y=13 To use the linear combination method and addition to eliminate the
antiseptic1488 [7]

Answer:

  A:  -2

Step-by-step explanation:

You want some factor k such that k(5x) +(10x) = 0. That is, 5k+10 = 0. The solution to this is k=-2, corresponding to selection A.

6 0
1 year ago
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The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . The
ziro4ka [17]

<em>Question:</em>

<em>Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. </em>

<em>The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . </em>

<em>The solution to the inequality is . </em>

<em>Sal’s mother would have to keep the second cell phone plan for at least months in order for it to be less expensive.</em>

Answer:

a. 150 + 51x < 100 + 55x

b. x > 12.5

c. At least 13 months

Step-by-step explanation:

Given

First Phone;

Cost = \$100

Additional = \$55 <em>(monthly)</em>

Second Phone;

Cost = \$150

<em />Additional = \$51<em> (monthly)</em>

<em></em>

Solving (a): The inequality

<em></em>

Represent the number of months with x

The first phone is expressed as:

100 + 55x

The second phone is expressed as:

150 + 51x

For the second to be less expensive that the first, the inequality is:

150 + 51x < 100 + 55x

Solving (b): Inequality Solution

150 + 51x < 100 + 55x

Collect Like Terms

51x-55x

-4x

Solve for x

x > -50/-4

x > 12.5

Solving (c): Interpret the solution in (b)

x > 12.5 implies 13, 14, 15....

Hence, She'll keep the second phone for a period of at least 13 months

4 0
1 year ago
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