2 years ago

If a cow has a mass of 9×10^2 kilograms, and a blue whale has a mass of 1.8×10^5 kilograms, which of these statements is true?

Mathematics

1 answer:

bonufazy [111]2 years ago

6 0

$\cfrac{1.8*10^5}{9*10^2}= 0.2*10^3 = 2*10^2=200$

<span>A.The blue whale has about 200 time more mass</span>

You might be interested in

Which is greater 9000cm or 2 km?

satela [25.4K]

Convert 2 km into cm

1 km = 100,000 cm

2 km = 200,000 cm

therefore 9,000 cm is greater

6 0

1 year ago

Explain why the graphing calculator cannot be used to solve or approximate solutions to all polynomial equations.

Triss [41]

Did your explanation include the following?

Some polynomial equations have complex solutions.

Therefore, complex solutions cannot be found by graphing the related system or function in the Cartesian (x-y) plane.

Polynomial functions with all complex solutions do not have x-intercepts, and the related system of equations will not intersect.

6 0

2 years ago

Read 2 more answers

Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 5, the length of B C is 3, and the length

svetoff [14.1K]

The side opposite to angle B is the side that does not contact with angle B.

In this attached image, you can see better that sides AB and BC is in contact with angle B. So, the opposite side to angle B is AC.

Therefore, the lenght of the side opposite to angle B is 4 units.

5 0

2 years ago

$5000 was invested into an investment that pays 4.25% simple interest. The total value of the investment amounted to $6593.75. H

Basile [38]

Answer:

7.5 years

Step-by-step explanation:

P = $5000,

R = 4.25%,

A = $6593.75,

N =?

SI = A - P = 6593.75 - 5000 =$1593. 75

$\because \: SI = \frac{ PNR}{100} \\ \\ \therefore \: 1593.75 = \frac{5000 \times N \times 4.25}{100} \\ \\ \therefore \: 1593.75 \times 100 = 21,250 \times N \\ \\ N = \frac{159375}{21250} \\ \\ N = 7.5 \: years \:$

6 0

2 years ago

Find the functions y-intercept algebraically

grigory [225]

To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y. If the equation is written in the slope-intercept form, plug in the slope and the x and y coordinates for a point on the line to solve y. Hope this helped! :)

3 0

2 years ago