A pair of fair dice is cast. what is the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one
1 answer:
If a pair of fair dice is cast, the probability that the <span>sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is given by:
The number of outcomes of sum of 9 where at last one is 3 is (3, 6) and (6, 3) = 2.
</span>The number of outcomes of last one of the numbers falling uppermost is a 3 is (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (1, 3), (2, 3), (4, 3), (5, 3) and (6, 3) = 11.
Therefore, <span>the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is 2 / 11.</span>
The number of outcomes of sum of 9 where at last one is 3 is (3, 6) and (6, 3) = 2.
</span>The number of outcomes of last one of the numbers falling uppermost is a 3 is (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (1, 3), (2, 3), (4, 3), (5, 3) and (6, 3) = 11.
Therefore, <span>the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is 2 / 11.</span>
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Answer:
Length of XM is 5.5 units.
Step-by-step explanation:
Given △XYZ where MZ is the angle bisector of ∠YZX . we have to find the length of XM.
A triangle with vertices X, Y, and Z. Side XZ is base. A line segment drawn from Z to M bisects ∠YZX into two parts ∠YZM and ∠XZM.
YZ=7 units, XZ=11 units and YM=3.5 units
By angle bisector theorem which states that an angle bisector of an angle divides the opposite side in two segments that are proportional to the another two sides of the triangle.
Hence,
⇒
⇒ MX=5.5 units.
Hence, length of XM is 5.5 units.
Distance
|a+bi| is the length of the vector from origin to (a,b).
|a+bi| is the length of the vector from origin to (a,b).