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Vanyuwa [196]
2 years ago
13

A pair of fair dice is cast. what is the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one

of the numbers falling uppermost is a 3?
Mathematics
1 answer:
WITCHER [35]2 years ago
5 0
If a pair of fair dice is cast, the probability that the <span>sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is given by:

\frac{P(sum\, of\, 9\, \cup\,3)}{P(3)}

The number of outcomes of sum of 9 where at last one is 3 is (3, 6) and (6, 3) = 2.

</span>The number of outcomes of last one of the numbers falling uppermost is a 3 is (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (1, 3), (2, 3), (4, 3), (5, 3) and (6, 3) = 11.

Therefore, <span>the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is 2 / 11.</span>
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The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2
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<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

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From the sequence of 6 independent rolls, 2 rolls can be chosen in ^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15 ways.

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2 years ago
Matthew manages the packaging department of his company. Yesterday, the department operated for only 4 hours due to a company pi
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Alright, lets get started.

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Hence, the required answer = 0.813

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