The range of scores in each interval of a grouped frequency distribution is called the

1 answer:

3 0

The answer is class intervals. A big set of data are grouped into different classes to get a hint of the distribution, and the range of such class of data is known as the Class Interval. In other words, these are range of scores in a group frequency distribution. Class intervals are commonly equal in width and are mutually exclusive. The middle of an interval is called a class mark and the ends of a class interval are called class limits. To calculate the class interval, divide the range by the number of classes.

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Step-by-step explanation:

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1 year ago

Which procedure justifies whether -3x(5-4)+3(x-6) is equivalent to -12x-6?

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Answer:

x=1

Step-by-step explanation:

-3x(5-4)+3(x-6)

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Using V = lwh, what is an expression for the volume of the following prism? The dimensions of a prism are shown. The height is S

Lubov Fominskaja [6]

<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

$V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}$

Substituting values:

$V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}$