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Sergio039 [100]
2 years ago
8

Seth’s father is thinking of buying his son a six-month movie pass for $40. With the pass, matinees cost $1.00. If matinees are

normally $3.50 each, how many times must Seth attend in order for it to benefit his father to buy the pass?
Mathematics
1 answer:
Ymorist [56]2 years ago
3 0

Answer:

In order for it to benefit his father to buy the pass Seth have to attend the movies for 11 times.

Step-by-step explanation:

Given:

Cost of movie pass = $40

Cost per matinees with pass = $1.00

Cost per matinees without pass = $3.50

To Find:

Number of times must Seth attend in order for it to benefit his father to buy the pass = ?

Solution:

Let x be the number of times he wants to visit

To profit his father

The number of visits without pass =  the number of visits with passin the cost  of $3.50

Then, without pass if he visits for x times then the cost will be  = 3.50x

Also with pass, the number of times he can visit the pass  =  \frac{40}{3.50}

then

\frac{350 x}{3.50} = \frac{40}{3.50}

3.50x = 40

x = \frac{40}{3.50}

x =  11.42

x = 11 (approx)

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icang [17]

Answer:

Amplitude increases and the period decreases

Step-by-step explanation:

Here, we are to compare amplitude change and period change

The first equation is;

y = sin x

The second is

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Generally, the equation of a sine graph can be written as;

y = a sin (bx + c)

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In the first equation , a = 1 while in the second , a = 3 ; This shows an amplitude increase

In the first equation, b = 1 while in the second equation b = 2/3; this shows a period decrease

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2 years ago
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Slav-nsk [51]
The rhombus has 2 obtuse angles, and 2 acute angles. the square has 4 right angles.
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2 years ago
The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.410.410, point, 4 years; th
kati45 [8]

Answer:

99.85%

Step-by-step explanation:

The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.4 years; the standard deviation is 1.9 years.

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The empirical rule states that for a normal distribution most of the data fall within three standard deviations (σ) of the mean (µ). That is  68% of the data falls within the first standard deviation (µ ± σ), 95% falls within the first two standard deviations (µ ± 2σ), and 99.7%  falls within the first three standard deviations (µ ± 3σ).

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68% falls within (10.4 ± 1.9). 68% falls within 8.5 years to 12.3 years

95% falls within (10.4 ± 2*1.9). 95% falls within 6.6 years to 14.2 years

99.7% falls within (10.4 ± 3*1.9). 68% falls within 4.7 years to 16.1 years

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1 year ago
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PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

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ANSWER:

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