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Alekssandra [29.7K]
2 years ago
10

Sully is a vocalist in a rock band. The table provided shows the number of tracks his band records and the respective number of

albums consisting of those recordings.
What is the rate of change of the number of tracks Sully’s band records with respect to each album the band releases?
A.
17 tracks per album
B.
2 tracks per album
C.
8 tracks per album
D.
6 tracks per album

Mathematics
2 answers:
Alina [70]2 years ago
6 0

Answer:

C

Step-by-step explanation:

The rate of change here will be the difference in the number of tracks divided by the difference in the number of albums.

Let's pick two random rows (it doesn't matter which two because they will produce the same result): (2, 16) and (4, 32).

The rate of change is: \frac{32-16}{4-2} =\frac{16}{2} =8

The answer is thus C.

Pavel [41]2 years ago
4 0

Answer:

C.

8 tracks per album

Step-by-step explanation:

16/2 = 8

32/4 = 8

48/6 = 8

64/8 = 8

80/10 = 8

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Answer:

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Step-by-step explanation:

When they were leaving

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There are exactly π radians in a semicircle. There are exactly π radians in a full circle. There are approximately radians in a
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The life expectancy of a particular brand of tire is normally distributed with a mean of 40,000 and a standard deviation of 5,00
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Answer: the probability that a randomly selected tire will have a life of exactly 47,500 miles is 0.067

Step-by-step explanation:

Since the life expectancy of a particular brand of tire is normally distributed, we would apply the formula for normal distribution which is expressed as

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σ = standard deviation

From the information given,

µ = 40000 miles

σ = 5000 miles

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2 years ago
A steel pipe 100 cm long has an outside diameter of 2 cm and an inside diameter of 1.8 cm. If thee density of the steel is 7.8 g
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Answer:

The mass of the pipe is 465\ g

Step-by-step explanation:

step 1

Find the volume of the steel pipe

The volume is equal to the area of outside circle minus the area of inside circle, multiplied by the length of the pipe

so

V=\pi [r2^{2}-r1^{2}]L

we have

r2=2/2=1\ cm ---> the radius is half the diameter

r1=1.8/2=0.9\ cm ---> the radius is half the diameter

L=100\ cm

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substitute

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step 2

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The mass is equal to the density multiplied by the volume

so

m=7.8(59.66)=465\ g

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