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VMariaS [17]
2 years ago
8

Sam kept track of the number of problems he was assigned for his math homework on the box plot. A number line goes from 0 to 28.

The whiskers range from 4 to 26, and the box ranges from 11 to 26. A line divides the box at 15. Which statement must be true according to the box plot?
Mathematics
2 answers:
Vanyuwa [196]2 years ago
6 0

Answer:

I think its A

The data is symmetric and shows that half of the assignments contained 15 problems or fewer.

Step-by-step explanation:

Orlov [11]2 years ago
3 0

Answer:

A.

Step-by-step explanation:

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Show how to make a ten to solve 13-7. Write the number sentence.
VARVARA [1.3K]
-7 + 3 + 10 = -4 + 10 = 10 - 4 = 6. 

To turn 13 into 10, you need to break it up into 10 + 3, which does not change the value of 13. Then, you add 3 to -7, which results in -4. Next, you add -4 to 10 (or rather, subtract 4 from 10), which results in 6. 

5 0
2 years ago
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Vinil7 [7]
Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

4 0
2 years ago
Bones Brothers &amp; Associates prepare individual tax returns. Over prior years, Bones Brothers have maintained careful records
madreJ [45]

Answer:

For this case we have the following info related to the time to prepare a return

\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation would be:

\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2

And the best answer would be

b. 2 minutes

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we have the following info related to the time to prepare a return

\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation would be:

\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2

And the best answer would be

b. 2 minutes

3 0
2 years ago
A certain company reported selling 5,000 toys during the month of January and expects sales to grow at a rate of 7.5% per month
artcher [175]
The formula is
Fv=p [(1+r)^(t)-1)÷r)
Fv ?
P 5000
R 0.075
T 6. June
Fv=5000 [(1+0.075)^(6)-1)÷0.075]
Fv=36220....answer

6 0
2 years ago
Read 2 more answers
The results of a race car are shown. Determine who drove the fastest. Explain.
monitta

We have to calculate speed for 1 lap for all of 'em.

Cutwright - 84/35 = 2.4 mins for 1 lap

Evans- 96.6/42 = 2.3 mins for 1 lap

Liza- 102.6/38 = 2.7 mins for 1 lap

 So, EVANS drove fastest among them as he took less time...

8 0
2 years ago
Read 2 more answers
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