<span>On an indifference curve, all bundles give the same amount of utility. (32,8) gives a utility of
U(32,8)=32x8=256
If (4,y) is on the same indifference curve, then it must give the same utility. Hence,
256 = 4y
y=64
64 bananas</span>
Answer:
<u>(h * h)(10) = 16</u>
Step-by-step explanation:
We should know that: (f*g)(x) = f(x)*g(x)
Given: h(x) = 6 - x
∴(h * h)(x) = (6-x) (6-x) = (6-x)²
To find (h * h)(10), substitute with x = 10 at (h * h)(x)
∴ (h * h)(10) = (6-10)² = (-4)² = 16
==============================================
Note: if we want to find (hoh)(10)
(hoh)(x) = h[h(x)] = 6 - (6 - x) = 6 - 6 + x = x
∴ (hoh)(10) = 10
Incomple question. However, here's the remaining part of the question:
14
2009
Meadow Fritillary= 5
Variegated Fritillary= 7
Zebra Swallowtail= 33
Eastern-Tailed Blue= 242
Louden County Butterfly Count
2010
Meadow Fritillary 34
Variegated Fritillary 95
Zebra Swallowtail 21
Eastern-Tailed Blue 168
2011
Meadow Fritillary
Variegated Fritillary
Zebra Swallowtail
Eastern-Tailed Blue
10
170
<u>Options</u>:
A) All butterfly populations are steadily decreasing.
B)All butterfly populations were larger than usual in 2010.
C)The Eastern-Tailed Blue butterfly is more common than the others.
D)The Meadow Fritillary is equally common as the Variegated Fritillary
Answer:
<u>C</u>
Step-by-step explanation:
Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.
Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.
2X+8=x-6
2x-x=-6-8
X=-6-8
X=-14
