Hello!
The range is all of the y-values of the function. As we can see, the function is at y-values 0, -2,-4 and -6.
Therefore, our answers are 0 ,-2 and -6.
I hope this helps!
Given
One month julia collected 8.4 gallons of rainwater.
she used 5.2 gallons of rainwater to water her garden
6.5 gallons of rainwater to water flowers
Find out how much was the supply of rainwater increased or decreased by the end of the month.
To proof
As given in the question
One month julia collected 8.4 gallons of rainwater
she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers
Total water she used in the month = 5.2 gallons + 6.5gallons
= 11.7 gallons
Let the supply of rainwater increased or decreased by the end of the month
be x .
Than the equation become in the form
x + 8.4 = 11.7
x = 3.3 gallons
Therefore the supply of rainwater increased or decreased by the end of the month is 3.3 gallons.
Hence proved
since its an isoscelies trangle, they probably wanted you to do base times height
make a 71-91/2-x x triangle
where x is the height of the triangle to the base 91 and 71 is the hypothenuse
and then do bh/2
or
use heron's formula
s= 71+91/2
area= 
have fun solving that
Answer:
See below in bold.
Step-by-step explanation:
Here is 1 grain on square 1 , 2 on square 2, 4 on square 3 and so on. This is a geometric sequence with the nth term = a1r^(n - 1) where a1 = first term , r = common ratio.
So the 20th term (the number of grains on square 20) would be
1*2^(20-1) = 524,288.
Total = a1 * (r^n - 1) / (r - 1)
= (2^20 - 1) / 2-1 = 1.048,575