So going+return=1356
return is 284 lesss than going
return=-284+going
subsitute
going-284+going=1356
2going-284=1356
add 284 to both sides
2going=1640
divide both sides by 2
going=820
so we havve
return=-284+going
return=-284+820
return=536
answer is return=536 miles
Shiela is 0.61 meters taller than her son.
Answer:
Step-by-step explanation:
<h3>Given</h3>
- Sofa = s
- Love seat = l
- Chair = c
- Sofa and love seat cost = $1300
- Sofa and 2 chairs cost = $1400
- Sofa, love seat and one chair cost = $1600
<h3>To find</h3>
<h3>Solution</h3>
<u>Equations as per given are:</u>
- s + l = 1300
- s + 2c = 1400
- s + l + c = 1600
<u>Subtract equation 1 from equation 3:</u>
- s + l + c - s - l = 1600 - 1300
- c = 300
<u>Considering this in the equation 2:</u>
- s + 2*300 = 1400
- s = 1400 - 600
- s = 800
<u>Substituting s in the equation 1:</u>
- 800 + l = 1300
- l = 1300 - 800
- l = 500
<u>Answer:</u> Love seat costs $500
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
Answer:-8x^2-6x+36xy^2+27y^2
Step-by-step explanation:
using the FOIL method