Answer:
D
Step-by-step explanation:
(4x√5x^2 +2x^2√6)^2
remove the last ^2 by multiplying the parenthesis by each other:
(4x√5x^2 +2x^2√6) * (4x√5x^2 +2x^2√6)
use FOIL & distribute :
4x√5x(4x√5x +2x^2√6) +2x^2√6(4x√5x +2x^2√6)
apply the distributive property once more:
4x^2√5(4x^2√5)+ 4x^2√5(2x^2√6) + (2x^2√6(4x^2√5) +2x^2√6(2x^2√6)
remove parenthesis and combine like terms to get:
104x^4+16x^4√30
answer is D
Answer: I think that the cost now from hotel 5 would be $15.00.
Step-by-step explanation:
5 hours = $5.00
10 hours = $10.00
15 hours = $15.00
20 hours = $20.00
25 hours = $25.00
Answer:
I think your functions are 
,
and 
If yes then then the third function which is .
Step-by-step explanation:
The function 
where c is a constant has
Domain : 
Range : ( 0 , ∞ )
The above range is irrespective of the value of c.
I have attached the graph of each of the function, you can look at it for visualization.
- <em> ⇒ </em>This function is same as so its range is <em>( 0 , ∞ )</em>.
- <em> ⇒ </em>If we double each value of the function
, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as <em>( 0 , ∞ )</em>.
- <em></em> ⇒ If we add 2 to each value of the function , which has range ( 0 , ∞ ), the lower limit will change as 0+2=2 but the upper limit will be same as ∞. Therefore the range will become as <em>( 2 , ∞ )</em>.
Answer:
C = 420/h + 400
Step-by-step explanation:
Let s be the side of the square base.
Let h be the height
Volume = s*h
20 = s*h
s = 20/h
Cost of glass is
5(20/h) + 5(4* h*20/h)
= 100/h + 400
Cost of frame is
2*4(20/h) + 2*4(20/h)
= 160/h + 160/h
= 320/h
Total cost = C
C = cost of glass + cost of frame
C = 100/h + 400 + 320/h
C = 420/h + 400
Answer:
.
Step-by-step explanation:
It is given that a number, x, rounded to 2 significant figures is 1300.
It is possible if,
1. The value of x is greater than of equal to 1250 and less than or equal to 1300.
i.e., 
...(1)
2. The value of x is greater than of equal to 1300 and less than 1350.
i.e., 
...(2)
On combining (1) and (2), we get
1350 is not included in the error interval for x.
Interval notation is .
Therefore, the error interval for x is .
