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Anon25 [30]
1 year ago
11

A meteorologist is studying the monthly rainfall in a section of the Brazilian rainforest. She recorded the monthly rainfall, in

inches, for last year. They were:
10.4, 10.3, 11.7, 11.1, 8.0, 4.4, 2.6, 1.8, 2.5, 4.4, 7.3, 9.5

Calculate the following for the data set:
Mathematics
1 answer:
mario62 [17]1 year ago
7 0

Answer:

Mean = 7

Median = 7.65

Mode = 4.4

Range = 9.9

Step-by-step explanation:

The question is incomplete as it doesn't state what to find. Lets complete the question first. The complete question states that:

Calculate the following for the data set

Mean

Median

Mode

Range

<h3>A) Mean</h3>

Mean = sum of values/ total number of values

Mean = 84/12

Mean = 7

<h3>B) Median</h3>

Arrange the data in ascending order

1.8, 2.5, 2.6, 4.4, 4.4, 7.3, 8.0, 9.5, 10.3, 10.4, 11.1, 11.7

Median = Average of middle values

Median = (7.3+8.0) / 2

Median = 7.65

<h3>C) Mode</h3>

Mode = number which appears most = 4.4

<h3>D) Range</h3>

Range = Max value - Min value

Range = 11.7 - 1.8

Range = 9.9

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Lynn mixes 39 pounds of water with 48 pounds of brick dust, so the mixture has a total weight of 39 + 48 = 87 pounds.

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2 years ago
The diagram shows several planes, lines, and points. Vertical plane P intersects horizontal plane R at line f. Vertical plane T
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Please mark brainliest

Answer:

Line H has points on planes R, T, P

Step-by-step explanation:

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Oni was timing her 100 meter sprints. Her first five sprints were 12.568 seconds, 11.426 seconds, 12.324 seconds, 11.981 seconds
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Answer:

Rounding to the nearest tenth and rounding to the nearest one hundredth.

Step-by-step explanation:

round all up or down then  line up and add

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11.426=  11

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add the totals then you see

60.83 sames as 61

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1 year ago
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\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;d=4\\&#10;n=10\\&#10;a_{10}=41&#10;\end{cases}&#10;\\\\\\&#10;41=a_1+(10-1)4\implies 41=a_1+36\implies \boxed{5=a_1}

thus

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and surely you know how much that is.
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