<span>8x3(3x2)=24x6 = True
</span><span>4x3(6x2)=24x6 = True
</span><span>6b^3(−2b3)=−12b^6 = Ture
</span><span>3a^3(−3a^4)=−9a^7 = True
They are all correct</span>
Answer:
Cross price elasticity using midpoint method = 0.56
Step-by-step explanation:
Using the mid-point method
Cross-price Elasticity of Demand = <u>% change in Quantity demanded of UPS</u>
% change of price of FedEx
%change in Quantity demanded of UPS
using Mid-point method = <u> Q2-Q1 </u> × 100
(Q1+Q2)÷ 2
= <u>1.3-1.2 </u> × 100
(1.2+1.3)÷2
= <u>0.1 </u> × 100
1.25
= 8%
% change in price of FedEx
using midpoint method =<u> P2-P1 </u>× 100
(P1+P2)÷ 2
=<u> 75-65 </u>× 100
(65+75)÷2
=<u> 10 </u> × 100
70
= 14.28%
Cross-price Elasticity of Demand = 8% ÷ 14.28%
using midpoint method = 0.56
Answer:
It depends on the cost of grapes.
Step-by-step explanation:
Half of 12 is 6, so if each pack of grapes cost 6 or less, she can buy a pack of green and red grapes.
All transportation (bus, cab, train) are all similarly likely to be selected, and 1 of them must be selected at morning and evening, so we get: P (bus) = P (cab) = P (train) = 1/3. We also have P(no cab in evening) = P(no cab at morning) = 2/3
Now, P(using cab exactly once) = P(cab at morning and no cab in the evening) + P(no cab at morning and cab in the evening)
= P(cab, no cab) + P(no cab, cab)
= 1/3 * 2/3 + 2/3 * 1/3
= 2/9 + 2/9
= 4/9
Probability that Elizabeth uses a cab only once is 4/9.
