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Bas_tet [7]
2 years ago
6

In a class of 30 students, 18 are men, 6 are earning a B, and no men are earning a B. If a student is randomly selected from the

class, find the probability that the student is a man or earning a B. A) .8 B) .24 C) .54 D) .4
Mathematics
1 answer:
alexandr402 [8]2 years ago
5 0

Answer:

0.8

Step-by-step explanation:

The question here says that In a class of 30 students, 18 are men, 6 are earning a B, and no men are earning a B. If a student is randomly selected from the class, find the probability that the student is a man or earning a B.

Since the question says that 18 out of 30 students are men,6 out of the remaining people earn a "B" and non of the 18 men earn a "B".

The probability of picking a man or a person that earns a "B" is

18/30 (since there are 18 men out of the 30 students)

And 6/30(since there are 6 people that earn a "b")

The probability of picking a man or a "b" earner is

18/30 + 6/30

= 24/30 or 0.8

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Answer:

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Step-by-step explanation:

Information given

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The margin of error is given by this formula:

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And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

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The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance level is \alpha=0.01 and the critical value would be z_{\alpha/2}=2.58, replacing into formula (b) we got:

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2 years ago
The weight of an apple is 150g rounded to the nearest 5g
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Answer:

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what is the lower bound weight of the apple

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Step-by-step explanation:

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When looking at probabilities, two ideas are always true.

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Idea #2 works here. (For example, think of how a die has six things and the probability of each is 1/6. So 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 1.) Let G = the probability of grape, C = probability of cherry and O = the probability of orange. From Idea #2, G + C + O = 1. Since we know G and C, then

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Answer:

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