Answer:
No, unless the function decides to follow a different pattern. See more explanation below.
Step-by-step explanation:
He is wrong, the table doesn't tell us what happens at x=6.
It does tell us the following:
1) When x=-4, f(x)=6.
2) When x=-2, f(x)=3.
3) When x=0, f(x)=-1.
4) When x=2, f(x)=-4.
So maybe he got it the x and f(x) value switched in his brain.
Because according to 1) x=-4 when f(x)=6.
If the points keep having x increase while y decreases, then every x>2 will have a y less than -4 correspond to it.
<span>the equation of a circle with the center at (h,k0 is given by the equation where the r is obviously the radius of the circle then do (x+3) ^2
(y-6)^2= 24 which shows that the center is = to (-3,6)
</span>
We need to find the biggest/highest number that can "go into" all of these numbers without a remainder.
That number is 2.
2 is a factor (a number that can "go into") of all of these numbers.
Answer:
Step-by-step explanation:
For the complex number 
the absolute value is 
Given the complex number 
For this complex number,
then the absolute value is
Answer:
(P(t)) = P₀/(1 - P₀(kt)) was proved below.
Step-by-step explanation:
From the question, since β and δ are both proportional to P, we can deduce the following equation ;
dP/dt = k(M-P)P
dP/dt = (P^(2))(A-B)
If k = (A-B);
dP/dt = (P^(2))k
Thus, we obtain;
dP/(P^(2)) = k dt
((P(t), P₀)∫)dS/(S^(2)) = k∫dt
Thus; [(-1)/P(t)] + (1/P₀) = kt
Simplifying,
1/(P(t)) = (1/P₀) - kt
Multiply each term by (P(t)) to get ;
1 = (P(t))/P₀) - (P(t))(kt)
Multiply each term by (P₀) to give ;
P₀ = (P(t))[1 - P₀(kt)]
Divide both sides by (1-kt),
Thus; (P(t)) = P₀/(1 - P₀(kt))
