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Advocard [28]
2 years ago
6

A new car is purchased for 17300 dollars. The value of the car depreciates at 9.25% per year. What will the value of the car be,

to the nearest cent, after the 15 years?
Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
4 0

Answer: 13

i got the question wrong and it told me the correct answer . thank me later

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The feet of a commemorative parabolic steel arch 100m high are 200m apart. Determine whether the focus of the arch is above or b
Neko [114]
<span>First of all, there should be coherence for the units of measurement -- either they are all meters or they are all ft. I would assume they are all ft. The correct answer is 75 ft above. T The explanation is the following: suppose the ground level is the x-axis, the 2 feet of the arch lie respectively on (0,0) and (100,0) on the ground level. Since the arch is 100ft high, the vertex of the parabola will be the point (100,100). Thus, we can find the equation describing the parabola by putting the three points we know in a system and we find that the equation of the parabola is y=(-1/100)x^2+2 To find the focus F, we apply the formula for the focus of a vertical axis parabola, i.e. F(-b/2a;(1-b^2+4ac)/4a). By substituting a=-1/100, b=2 and c=0 into the formula, we find that the coordinates of the focus F are (100,75). So we conclude that the focus lies 75ft above ground.</span>
7 0
2 years ago
Read 2 more answers
Three identical circular coins are lined up in a row as shown (the 10s represent their value, not a length). The distance betwee
son4ous [18]

Answer:

Diameter of a circle = 1.6 Cm

Step-by-step explanation:

Given:

Distance between first and third coins = 3.2 cm

Find:

Diameter of the coins = ?​

Computation:

Number of circle = 3

In the given figure,distance between the first and third coins is 3.2 cm.

So,

Distance = 1st circle radius + 2nd circle diameter + 3rd circle radius

Distance = 1st circle radius + 2 (radius) + 3rd circle radius

Distance = R + 2R + R

3.2 Cm = 4 R

Radius = 0.8 Cm

Diameter of a circle = 2 × radius

Diameter of a circle = 2 × 0.8

Diameter of a circle = 1.6 Cm

3 0
2 years ago
A coat at a store is originally priced at 54.99.The store marks the price down to 32.99.To the nearest percent ,what is the perc
AnnZ [28]
For this case what we can do is the following rule of three:
 54.99 ------> 100%
 32.99 ------> x
 We clear the value of
 x = (32.99 / 54.99) * (100)
 x = 59.99272595
 Therefore, the discount percentage is:
 100-59.99272595 = 40.00727405%
 To the nearest percent;
 40%
 Answer:
 
The percent markdown of the coat is:
 
40%
7 0
2 years ago
) The GPA of accounting students in a university is known to be normally distributed. A random sample of 20 accounting students
katen-ka-za [31]

Answer:

The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549

Step-by-step explanation:

We are in posessions of the sample's standard deviation. So we use the student's t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975([tex]t_{975}). So we have T = 2.0930

The margin of error is:

M = T*s = 2.0930*0.16 = 0.3349.

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 2.92 - 0.3349 = 2.5851

The upper end of the interval is the sample mean added to M. So it is 2.92 + 0.3349 = 3.2549

The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549

4 0
2 years ago
15. Snazzy Sneakers has a shoe sale. Anthony buys 4 pairs of shoes. How can you represent this? Choose all that apply.
olga55 [171]

Answer:

8

Step-by-step explanation:

I dont really get the question so i thought it was 15 - 7??

6 0
2 years ago
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