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ValentinkaMS [17]
2 years ago
8

Which statement best describes the excluded values of a rational expression?

Mathematics
2 answers:
goblinko [34]2 years ago
7 0

Answer: b. The number of excluded values of a rational expression cannot exceed the degree of the denominator.

Step-by-step explanation:

A rational expression is a fraction in which the numerator and the denominator are polynomials. The excluded values of a rational number are that values which make denominator zero.They are basically the zeroes of the polynomial of denominator.So,the number of excluded values can't exceed the degree of the denominator.

Here is  a rational expression  \frac{x^2-6}{x^2-4}

where the denominator is x^2-4=(x-2)(x+2)

⇒x=-2,+2 are zero of polynomial x^2-4

i.e. -2 and 2 are the excluded values for the whole rational expression.



Liono4ka [1.6K]2 years ago
7 0

Which statement best describes the excluded values of a rational expression?

B is the correct answer - The number of excluded values of a rational expression cannot exceed the degree of the denominator.

A rational expression is denoted in \frac{p}{q} form; where 'p' is the numerator and 'q' is the denominator. The numerator and denominators can be polynomials. The denominator cannot be zero in general, as it makes the fraction  value undefined.

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in the figure below line de is parallel to line f g with a transversal AG write and solve a system of liner equation to determin
Kay [80]
The complete question in the attached figure

we know that

angle y and angle (5y-18) are supplementary angles
then
y°+(5y-18)°=180°------> 6y=180+18------> y=198/6-----> y=33°
and
angle x and angle y are also supplementary angles
then
x+y=180--------> x=180-y-----> x=180-33-----> x=147°

the answer is
x=147°
y=33°

7 0
2 years ago
give an example on an addition problem in which you would and would not group the addends differently to add
Murrr4er [49]
Addends are any of the numbers added together in an equation. 

The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations. 

For ex:
2 - (8 + 3)  here, the 8 and 3 have to be grouped together before doing the subtraction.

Any addition problem without parentheses can be used for one where the grouping doesn't matter
3 0
2 years ago
Weight of a rock: In a geology course, students are learning to use a balance scale to accurately weigh rocks. One student plans
statuscvo [17]

Answer:

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

Step-by-step explanation:

What is Confidence Interval?

The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.  

The confidence interval is given by

CI = \bar{x} + t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\

Where \bar{x} is the mean weight \sigma is the standard deviation t_{\alpha/2} is the critical value from t-table and n is the sample size.

The term t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) is known as margin of error.

As the sample size is decreased the corresponding margin of error increases which results in wider confidence interval which means smaller precision.

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

We can say with 95% confidence that the true mean weight of the rock is within the interval of (25.2, 29.1).

7 0
2 years ago
The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced
Dahasolnce [82]

Answer:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.86,0.13)  

Where \mu=5.86 and \sigma=0.13

We are interested on this probability

P(5.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

4 0
2 years ago
Rename the number 805 tens=
zhuklara [117]
805 tens
805x10=8050
805 tens is 8050
6 0
2 years ago
Read 2 more answers
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