The probability of the first event happening is 1/10 or 0.1
If Ann puts the ball back, there are still 10 balls of which, Ann removed 1. Therefore the probability of the second event is also 0.1.
0.1x0.1=0.01, which is the probability that both women removed the same ball
12 + x = 0.80(20+x)
12 + x = 16 + 0.80x
12 = 16 -0.2x
-4 = -0.2x
x = -4/-0.2 = 20
they need to win 20 more games
Answer:
y = 4 or y = 6
Step-by-step explanation:
2log4y - log4 (5y - 12) = 1/2
2log_4(y) - log_4(5y-12) = log_4(2) apply law of logarithms
log_4(y^2) + log_4(1/(5y-12)) = log_4(/2) apply law of logarithms
log_4(y^2/(5y-12)) = log_4(2) remove logarithm
y^2/(5y-12) = 2 cross multiply
y^2 = 10y-24 rearrange and factor
y^2 - 10y + 24 = 0
(y-4)(y-6) = 0
y= 4 or y=6
Answer:

Step-by-step explanation:
Given


Required
Represent as an equation;

Expand the above

<em>Recall that b = $10 ----given</em>
becomes


Distance from tip of shadow to lamp post = 13 +9 feet = 22 ft
Height of lamp post = x
tan 50 = x /22 = 1.192
x = 22 * 1.192 =.26.2 ft. rounded = 26ft