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a_sh-v [17]
2 years ago
11

A rectangular lot is bounded on one side by a river and on the other three sides by a total of 80m of fencing. Find the dimensio

ns of the lot with the largest possible area
Mathematics
1 answer:
vova2212 [387]2 years ago
5 0
Hello,

Let 's a the width,
b the heigth

2a+b=80==>b=80-2a

Area=A(a,b)=a*b=a*(80-2a)
=-2a²+80a
=-2(a²-2*20a+20²-20²)
=-2(a-20)² +800
Area is maxi if a=20 and area max=800


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Iteru [2.4K]

Answer:

The number of bacteria B after d days is given by

B = B_0 (3)^{\frac{1}{10} d}

where B_0 is the initial number of bacteria.  

Step-by-step explanation:

The number of bacteria B in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

B = B_0 *3,

where B_0 is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

B = (B_0 *3)*3

after the 3rd day,

B =( B_0 *3*3)*3

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

B = B_0 (3)^n

where n is is the <em>n</em>th 10-days.

Since, n is 10 days, we have

d =10n

or

n =\dfrac{1}{10}

Substituting that into B = B_0 (3)^n, we get:

\boxed{ B = B_0 (3)^{\frac{1}{10} d}}

8 0
2 years ago
In the roof truss, line BG bisects ∠ABC and ∠DEF, m∠ABC= 112°, and ∠ABC≅∠DEF.
Dennis_Churaev [7]

In the given diagram,  line BG bisects ∠ABC and ∠DEF, m∠ABC= 112°, and ∠ABC≅∠DEF.  So the measure of angles are :

1. m∠DEF=  112° because ∠ABC≅∠DEF

2. m∠ABG=  56° because a straight line BG is bisecting ∠ABC in two equal parts. So, \frac{112}{2} = 56

3. m∠CBG=  56° because ∠ABG and ∠CBG are equal.

4. m∠DEG=  56° because ∠ABG ≅ ∠DEG


7 0
2 years ago
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A researcher gathers data on the length of essays​ (number of​ lines) and the SAT scores received for a sample of students enrol
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Answer:

(C) The slope of the regression equation is not significantly different from zero

Step-by-step explanation:

Let's suppose that we have the following linear model:

y= \beta_o +\beta_1 X

Where Y is the dependent variable and X the independent variable. \beta_0 represent the intercept and \beta_1 the slope.

In order to estimate the coefficients \beta_0 ,\beta_1 we can use least squares estimation.

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_1 = 0

Alternative hypothesis: \beta_1 \neq 0

Or in other wouds we want to check is our slope is significant.

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal

The significance level is provided and on this case is \alpha=0.05

The standard error for the slope is given by this formula:

SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

Th degrees of freedom for a linear regression is given by df=n-2 since we need to estimate the value for the slope and the intercept.

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_1}{SE_{\beta_1}}

The confidence interval for the slope would be given by this formula:

\hat \beta_1 + t_{n-2, \alpha/2} \frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

And using the last formula we got that the confidence interval for the slope coefficient is given by:

-0.88 < \beta_1

IF we analyze the confidence interval contains the value 0. So we can conclude that we don't have a significant effect of the slope on this case at 5% of significance. And the best option would be:

(C) The slope of the regression equation is not significantly different from zero

6 0
2 years ago
Which answer choice contains all the factors of 10
RSB [31]
Factors of 10 are : 1,2,5,10
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Answer:

2.8, 8.8, and -17 respectively.

Step-by-step explanation:

We need to find roots of the equation.

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2 years ago
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