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Natalka [10]
2 years ago
9

A researcher gathers data on the length of essays​ (number of​ lines) and the SAT scores received for a sample of students enrol

led at his university. Based on his regression​ results, the​ 95% confidence interval for the slope of the regression equation is minus−0.88 to 1.34. At alphaαequals=​0.05, which of the following statements is​ true? (A) There is a statistically significant association between length of essays and SAT score.(B) The relationship between length of essays and SAT scores is significant and negative.(C) The slope of the regression equation is not significantly different from zero.(D) The slope of the regression equation is significantly different from zero.
Mathematics
1 answer:
LenaWriter [7]2 years ago
6 0

Answer:

(C) The slope of the regression equation is not significantly different from zero

Step-by-step explanation:

Let's suppose that we have the following linear model:

y= \beta_o +\beta_1 X

Where Y is the dependent variable and X the independent variable. \beta_0 represent the intercept and \beta_1 the slope.

In order to estimate the coefficients \beta_0 ,\beta_1 we can use least squares estimation.

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_1 = 0

Alternative hypothesis: \beta_1 \neq 0

Or in other wouds we want to check is our slope is significant.

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal

The significance level is provided and on this case is \alpha=0.05

The standard error for the slope is given by this formula:

SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

Th degrees of freedom for a linear regression is given by df=n-2 since we need to estimate the value for the slope and the intercept.

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_1}{SE_{\beta_1}}

The confidence interval for the slope would be given by this formula:

\hat \beta_1 + t_{n-2, \alpha/2} \frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

And using the last formula we got that the confidence interval for the slope coefficient is given by:

-0.88 < \beta_1

IF we analyze the confidence interval contains the value 0. So we can conclude that we don't have a significant effect of the slope on this case at 5% of significance. And the best option would be:

(C) The slope of the regression equation is not significantly different from zero

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2 years ago
The graph represents the function where electricity usage in kilowatts per hour of a clock radio varies directly with the number
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Answer:

Reasonable estimation for constant of variation is 0.25 kWh per day.    

Step-by-step explanation:

We are given the following information in the question:

  • The graph represents the function where electricity usage.
  • Electricity usage in kilowatts per hour of a clock radio varies directly with the number of days.
  • The x-axis shows the number of days and usage in kilo-watt per hour is showed on the y-axis.
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Formula for constant of variation:

\displaystyle\frac{y_2-y_1}{x_2-x_1}

Putting the values from the coordinates (2,0.5) and (6,1.5), we get:

\displaystyle\frac{1.5-0.5}{6-2} = \frac{1}{4} = 0.25\text{ kilowatt-hours per day}

Hence, reasonable estimation for constant of variation is 0.25 kWh per day.

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Pete traveled 1,380 miles in two days. The first day, he traveled 1.5 times as far as he did the second day. How many miles did
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A is the solution.
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"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the
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Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

 Expected observed Diff

x p(x) p(x)*1000  

   

0 0.002 2  

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144  

5 0.189 189  

6 0.238 238  

7 0.178 178  

   

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.  

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How many solutions are there to the system of equations?
hichkok12 [17]

Answer: The system of equations has NO SOLUTION.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Given the following system of equations:

\left \{ {{4x-5y=5} \atop {-0.08x+0.10y=0.10}} \right.

Write the first equation and solve for "y" in order to express it in Slope-Intercept form:

4x-5y=5\\\\-5y=-4x+5\\\\y=\frac{-4x}{-5}+\frac{5}{-5}\\\\y=0.8x-1

You can identify that:

m=0.8\\b=-1

Apply the same procedure with the second equation. Then:

-0.08x+0.10y=0.10\\\\0.10y=0.08x+0.10\\\\y=\frac{0.08x}{0.10} +\frac{0.10}{0.10}\\\\y=0.8x+1

You can identify that:

m=0.8\\b=1

The slopes of both lines are equal, therefore  the lines are parallel and the system has NO SOLUTION.

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2 years ago
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