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2 years ago

To solve the equation y – 4 = 9 for y, what operation must be applied to both sides in order to isolate the variable y?

Mathematics

1 answer:

inna [77]2 years ago

7 0

Answer:

$y-4=9$

The opposite of subtraction is addition, so you would have to add 4 to both sides:

$y-4+4=9+4$

$y=13$

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In the graph, the amount of sales tax (t) is proportional to the price (p) of an item.

shusha [124]

Answer:

i would guese c

Step-by-step explanation:

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2 years ago

Which situation can be modeled by the inequality 50−12x≥8?

Nadya [2.5K]

4⅚ ≥ x; subtract fifty-eight from both sides, divide by -12 from both sides, and you will have your answer.

NOTE: This is where you reverse your inequality symbol [dividing or multiplying by a negative].

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2 years ago

Read 2 more answers

A composition of transformations ΔKLM maps ΔK"L"M" to . Triangle K L M is rotated 270 degrees about point P to form Triangle K p

telo118 [61]

Answer:

a 270° rotation about point P

Step-by-step explanation:

Because after transformation MK and M'K 'are at 90°, that implies that MK is rotated as 90 ° clockwise around P or 270 ° counterclockwise around P.

Therefore the transformation composition that maps $\triangle KLM$ to $\triangle$ K"L"M",

So, for this composition, the first transformation is 270° is the 270° rotation i.e to be counterclockwise about point P.

While the transformation of the second would be down translation that goes to the right.

hence, the last option is correct

6 0

2 years ago

Read 2 more answers

Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u

soldier1979 [14.2K]

$x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }$

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

$p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}$

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

$\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}$

$\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}$

$\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}$

Therefore:

$\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]$

Recall that at t=25, $p(25)=\dfrac { 5800 } {13} \approx 446.15$

Therefore:

$\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009$

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0

2 years ago

Lesson 3 homework practice mean absolute deviation

Natali5045456 [20]

Assuming that am supposed to calculate the the mean absolute deviation of
1,2,3,4,5,6,7
mean absolute deviation is calculated by first calculating the mean;
(1+2+3+4+5+6+7) =28/7
= 4
Then, find the absolute value (the difference between each value in the data and the mean) (x-μ)
= -3,-2,-1,0,1,2,3
Absolute values= 3,2,1,0,1,2,3
Then we find the mean of the values,
3+2+1+0+1+2+3 = 12
= 12/7
= 1.7143
Therefore, the mean is 4, and the Mean absolute deviation is 1.7143

4 0

2 years ago