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Sergeeva-Olga [200]

2 years ago

7

Fast Freddie is a widget assembler. He is paid $3.27 for every widget he assembles. What is Freddie's total pay for a week in wh

ich he completes 209 widgets?

2 answers:

ddd [48]2 years ago

8 0

Use your calculator to solve 3.27*209

Ymorist [56]2 years ago

4 0

Answer:

683.43

Step-by-Step explanation:

Use you're calculator and multiply 3.27*209

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The yearly cost in dollars, y, for a member at a video game arcade based on total game tokens purchased, x, is y =y equals Start

const2013 [10]

Answer:

$y = \frac{1}{5}x$

Step-by-step explanation:

Given

Yearly Cost for members; $y = \frac{1}{10}x + 6$

Required

Determine the yearly cost for non members

From the question, we understand that:

<em>A non member pays $0.20 for each game;</em>

Yearly cost is then calculated as thus;

y = Amount * Number of Games

Where:

Amount = $0.2 and Number of Games = x

$y = 0.20 * x$

Convert 0.2 to fraction

$y = \frac{2}{10} * x$

Divide the numerator and the denominator by 2

$y = \frac{1}{5} * x$

$y = \frac{1}{5}x$

<em>Hence, the yearly cost for non members is </em>

$y = \frac{1}{5}x$

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2 years ago

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The 6 elephants at the zoo have a combined weight of 11,894 pounds. About how much does each elephant weigh?

Sidana [21]

Answer: 14,000 i think

Step-by-step explanation:

3 0

1 year ago

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The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) = (e^-x/1076)/

kozerog [31]

Answer:

(a) 0.06154

(b) 0.2389

(c) 0.6052

(d) 2478

Step-by-step explanation:

probability density function of the time to failure of an electronic component in a copier (in hours) is

P(x) = 1/1076e^−x/1076

λ = 1/1076

A) A component lasts more than 3000 hours before failure:

P(x>3000) = 1 − e^−3000/1076

= 0.06154

B) A component fails in the interval from 1000 to 2000 hours:

P(1000>x>2000) =1 − e^−2000/1076 − 1 +e^−1000/1076 = e^−1000/1076 − e^−2000/1076 = 0.3948 − 0.1559

= 0.2389

C) A component fails before 1000 hours:

P(x<1000) = 0.6052

D) The number of hours at which 10% of all components have failed:

e^−x/1076 = 0.1

= −x/1076

= ln(0.1)

x =(2.3026)×(1076)

x = 2478

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2 years ago

Solve: 1/3a2 - 1/a =1/6a2 The solution is a =

aleksklad [387]

Solve the rational equation by combining expressions and isolating the variable aa.

a≈−0.16641103,1.49400147

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2 years ago

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Find all explicit solutions y = ϕ(x) of the DE in part (a) defined by this relation. Give the interval I of definition of each e

Evgen [1.6K]

Answer and Step-by-step explanation:

Firstly, by definition, an interval of definition of any solution is the open interval on which it is defined.

Consider the problem p′=p², p(0)=1, has solution p(t) = 1/(1−t).

The definition of this solution is on the interval (−1/2,1/3), making it an interval of definition of solution.

However, it isn't the largest. The largest interval of definition is (−∞,1).

Consider another problem: p(t)=t√ satisfies the ODE p′=1/(2p).

Meanwhile, when considered as the solution of the ODE above, the domain of square root is [0,∞), and the interval of definition is (0,∞).

But at t=0 the ODE makes no sense, so it would be wrong to assume that y satisfies the ODE in this case. Meanwhile, ODEs are generally considered only on open intervals.

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2 years ago