Answer: <em>
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Step-by-step explanation:
<h3>
<em>
The complete exercise is:"A gardener has 27 tulip bulbs, 45 tomato plants, 108 rose bushes, and 126 herb seedlings to plant in the city garden. He wants each row of the garden to have the same number of each kind of plant. What is the greatest number of rows that the gardener can make if he uses all the plants?"</em></h3><h3 />
The first step to solve the exercise is to find the Greatest Common Factor (GCF) between 27, 45, 108 and 126.
You can follow these steps in order to find the GCF:
1. You must decompose 27, 45, 108 and 126into their prime factors:

2. You must multiply the commons with the lowest exponents. Then:
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Therefore, the greatest number of rows that the gardener can make if he uses all the plants is:

Answer:
Step-by-step explanation:
a )
sample mean = sum total of given data / no of data
= 415.35 / 20 = 20.76
To calculate the median we arrange the data in ascending order and take the average of 10 th and 11 th term .
= 20.50 + 20.72 / 2
= 20.61
b ) To calculate the 10% trimmed mean , we neglect the largest 10% and smallest 10 % data and then calculate the mean . Here we neglect the first two smallest and last two greatest
(18.92 + 19.25 ..... + 22.43 + 22.85) / 16
= 20.74
c )
We can easily plot the data on number line from 17 to 24
d )
Maximum value of data set = 23.71 and minimum value is 18.04
mean is 20.76 , median is 20.61 and trimmed mean is 20.74
They are between maximum and minimum values of given data . Hence there is no outliers .
Answer:
Answer E
Step-by-step explanation
The statement gives a probability of approximately 0.022 for the difference in sample proportions, pˆA−pˆS, being greater than 0.
Answer:112,112,68
Step-by-step explanation:
You have the answer in the picture. You only need S and is 180-Q =180-68= 112, so the answer is 112,112,68