Answer:
Bill launched a model rocket, and estimated its height h, In feet, after 1 seconds. His results are shown in the table
Time, 1 0 1 2 3 4
Height, h 0 110 190 240 255
Bill's data can be modeled by the function h(t) = -1612 + 128.
Which value is the best prediction for the height of the rocket after 5.5 seconds?
A 150 ft
B. 180 ft
C. 220 ft
D. 250 ft
E 260 ft
The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is
for the mean chart
uclim= x+A2xR
where x = sum(of the value) / number of each value
and for
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin
in the case of the sample 1: S1
the data are:
79.2 78.8 80.0 78.4 81.0
the mean is x1 = (</span>79.2 + 78.8 + 80.0 + 78.4 + 81.0) / 5= 79.48
<span>its range is R 1= 81.0 -78.4 = 2.6
we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14 , R2=2.3
</span>S3: x3= 80.14 , R3=1.2
S4: x4= 79.60 , R4=1.7
S5: x5= 80.02 , R5=2.0
S6: x6=80.38 , R6=1.4
<span>
therefore the average value is X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95 and lclim is always equal to 0, because D3=0
we can say that the process is not in control.
</span>
Answer: The number of pounds each camel have to carry=44 pounds
The pounds of goods left=3 pounds
Step-by-step explanation:
The total pounds of goods the merchant have=
=487 pounds
The total number of camels the merchant have = 11
If each camel carry same weight of goods, then we divide total weight by 11, we get
487÷11=44.27
The number of pounds each camel have to carry=44 pounds
The pounds of goods left=487-44×11=487-484=3 pounds
Answer:
0.058 is the required probability.
Step-by-step explanation:
We are given the following PMF in the question:
x: 0 1 2
p(x): 0.24 0.15 0.61
Z can take values 0, 1, 2, 3, 4.
We have to compute the value of P(Z=0)
Thus,
