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2 years ago

What is the domain and range of the function y = xn if n is an odd whole number? if n is an even whole number?

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

8 0

Answer:

Step-by What is the domain and range of the function y = xn if n is an odd whole number? if n is an even whole number?-step explanation:

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A delivery truck drove 203 miles in 3.5 hours. After unloading and loading new cargo, it traveled on another 243 miles for 4.5 h

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Answer:

55.75

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2 years ago

Ashley plants a tree 45cm tall it grows by 10 cm each year. Find the amount ashley gets in the 5th year?

Genrish500 [490]

Answer:

95cm

Step-by-step explanation:

45cm is the initial height

each year grow 10cm

growing time 5 years

45+(10 × 5)=95 cm

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2 years ago

This relationship is given by the equation, v = gt. In this equation, g is the acceleration due to gravity, t is the number of s

DENIUS [597]

v=gt,

Initial value when time t=0, v=g*0=0.

t=0 s, v=0 m/s means that object’s initial velocity 0 m/s.

v=gt, and g is a constant g=9.8 m/s². We can write v=9.8*t.

Rate of change 9.8 means the acceleration due to gravity is 9.8 m/s².

Answer: C. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.

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1 year ago

Agent Hunt transferred classified files from the CIA mainframe onto his flash drive. The drive had some files on it before the t

topjm [15]

Answer: The drive was 24.32% full when the transfer began.

Step-by-step explanation:

Given: The rate of transferring file = 4.44 megabytes per second.

After 32 seconds, the amount of data on the drive = 384 megabytes

The amount of transferred data = $32\times4.4=140.8$ megabytes

Therefore, the amount of data in the drive at the beginning is given by :-

$\text{Beginning amount=Amount after 32 seconds -Amount transferred}\\\\\Rightarrrow\ \text{Beginning amount=}384-140.8=243.2$

The drive had a maximum capacity of 1000 megabytes.

$\frac{243.2}{1000}\times100=24.32\%$

Hence, the drive was 24.32% full when the transfer began.

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1 year ago

Read 2 more answers

se the function to show that fx(0, 0) and fy(0, 0) both exist, but that f is not differentiable at (0, 0). f(x, y) = 9x2y x4 + y

alexandr1967 [171]

Answer:

It is proved that $f_x, f_y$ exixts at (0,0) but not differentiable there.

Step-by-step explanation:

Given function is,

$f(x,y)=\frac{9x^2y}{x^4+y^2}; (x,y)\neq (0,0)$

To show exixtance of $f_x(0,0), f_y(0,0)$ we take,

$f_x(0,0)=\lim_{h\to 0}\frac{f(h+0,k+0)-f(0,0)}{h}=\lim_{h\to 0}\frac{\frac{9h^2k}{h^4+k^2}-0}{h}\\\therefore f_x(0,0)=\lim_{h\to 0}\frac{9hk}{h^4+k^2}=\lim_{h\to 0}\frac{9k}{h^3+\frac{k^2}{h}}=0$ exists.

And,

$f_y(0,0)=\lim_{k\to 0}\frac{f(h,k)-f(0,0)}{k}=\lim_{k\to 0}\frac{9h^2k}{k(h^4+k^2)}=\lim_{k\to 0}\frac{9h^2}{h^4+k^2}=\frac{9}{h^2}$ exists.

To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,

$\lim_{(x,y)\to (0,0)}\frac{9x^2y}{x^4+y^2}=\lim_{x\to 0\\ y=mx^2}\frac{9x^2y}{x^4+y^2}=\frac{9x^2\times m x^2}{x^4+m^2x^4}=\frac{9m}{1+m^2}$ where m is a variable.

which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).

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2 years ago