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2 years ago

The total length of two ribbons is 13 meters. If one ribbion is 7 5/8 meters long what is the length of the other ribbon

Mathematics

2 answers:

Naddik [55]2 years ago

8 0

The length of the other ribbon is $5\frac{3}{8}$ meters.

<h3>Further Explanation</h3>

Let's say that:

First ribbon = x

Second ribbon = y

<u>Given:</u>

From the above we get the information:

x = $7\frac{5}{8}$ meters

x + y = 13 meters

<u>Question:</u>

What is the length of the other ribbon?

First step we need to change the mixed fraction into improper fraction as follow:

$x = 7\frac{5}{8} = \frac{61}{8}$

$x + y = 13$ so $y = 13-x$

$\boxed {y= 13 - \frac{61}{8} }\\\boxed {y = \frac{104-61}{8} = \frac{43}{8} = 5\frac{3}{8} }$

so the length of the other ribbon is $5\frac{3}{8}$

For subtraction or additional fraction, when the denominators is different, we need to find the common denominator for both number.

<h3>Learn more</h3>

Part to whole relationship brainly.com/question/11677654

Subtraction fraction brainly.com/question/2954545

Mixed fraction brainly.com/question/745462

<h3 />

Keywords: additional fraction, subtraction fraction, mixed fraction, improper fraction

Liono4ka [1.6K]2 years ago

5 0

Perhaps the easiest way to solve this problem is to convert 13 into a fraction that has the same denominator as 7 5/8.
Convert both to improper fractions:
7 5/8 turns into 61/8, and
13 turns into 104/8.

Then, subtract 61/8 from 104/8:
104/8-61/8=43/8.
Simplify (mixed fraction):
5 3/8.

The second ribbon has a length of 5 3/8 meters.

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Rina8888 [55]

Answer:

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b=-9

c=9

d=3

e=3

f=2

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Step-by-step explanation:

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2 years ago

A point is dilated with respect to the origin. Determine the value of K and state whether the dilation is an expansion or contra

vlabodo [156]

Scale Factor (K) = (new length/measure)/ (original length/measure)
for x-coordinate = 8/2 = 4
for y-coordinate = 16/4 = 4

K=4, expansion

K is the representation of "scale factor". Scale factor is the ratio of the lengths involved of the similar figures. It can be used to identify the kind of dilation, whether it is contraction or expansion. If the Scale Factor is greater than 1, then that means expansion and if it is less than 1, then it signifies contraction.

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2 years ago

among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play

kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0

2 years ago

I talk to an average of 8 customers per hour during an 8 hour shift and need to increase the amount of customers i help by 20%,

lbvjy [14]

Answer:

The number of customer needed to achieve is 34

Step-by-step explanation:

Given as :

The number of customer per hour = 8

The time taken = 8 hours

The rate of increase = 20 %

Let The increase in number of customer after 20 % increment = x

So , The number of customer after n hours = initial number × $(1+\dfrac{\textrm rate}{100})^{n}$

or, The number of customer after 8 hours = 8 × $(1+\dfrac{\textrm 20}{100})^{8}$

or, The number of customer after 8 hours = 8 × 4.2998

∴The number of customer after 8 hours = 34.39 ≈ 34

Hence The number of customer needed to achieve is 34 answer

8 0

2 years ago

A house on the land measures 45 feet by 38 feet,a wooded area covers 118 feet by 60 feet,and the front yard is 78 feet by 40 fee

den301095 [7]

Rectanglearea=legnth timees width
triagnlearea=1/2base times height

ok so we find volume of entier land first

we can cut into triangle an rectangle

triangle=height=650-200=450
base=600
area=1/2*600*450=135000 ft^2

rectangle=200 times 600=120000

add
135000+120000=255000ft^2

find other areas and subtract
areahouse=45*38=1710
areawooded=118*60=7080
frontyard=78*40=3120
add
1710+7080+3120=11910

minus

255000-11910=243090

how many acres are farmed

43560ft^2=1acre
divide both sides by 43560
1ft^2=1/43560 acre

multiply both sides by 243090
243090ft^2=243090/43560acre=5.5805acre=5.6acre rounded

answer is 5.6 acer

6 0

2 years ago