P=i/rt
P=1687.5/(0.09*10/12)
P=22500
Incomple question. However, here's the remaining part of the question:
14
2009
Meadow Fritillary= 5
Variegated Fritillary= 7
Zebra Swallowtail= 33
Eastern-Tailed Blue= 242
Louden County Butterfly Count
2010
Meadow Fritillary 34
Variegated Fritillary 95
Zebra Swallowtail 21
Eastern-Tailed Blue 168
2011
Meadow Fritillary
Variegated Fritillary
Zebra Swallowtail
Eastern-Tailed Blue
10
170
<u>Options</u>:
A) All butterfly populations are steadily decreasing.
B)All butterfly populations were larger than usual in 2010.
C)The Eastern-Tailed Blue butterfly is more common than the others.
D)The Meadow Fritillary is equally common as the Variegated Fritillary
Answer:
<u>C</u>
Step-by-step explanation:
Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.
Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.
Answer:
The correct set of hypotheses is
: d=80 degrees
: d>80 degrees
Step-by-step explanation:
The weatherman claims that the average temperature during July in Chattanooga is 80 degrees or less. To test this claim, following hypotheses need to be taken:
Let d be the the average temperature during July in Chattanooga, then
: d=80 degrees
: d>80 degrees
The Answer is B: 2,125 cm²
n = 7
a = 24.18 cm
r = 25.1051 cm
R = 27.8646 cm
A = 2124.65 cm²
P = 169.26 cm
x = 128.571 °
y = 51.4286 °
Agenda:
r = inradius (apothem)
R = circumradius
a = side length
n = number of sides
x = interior angle
y = exterior angle
A = area
P = perimeter
π = pi = 3.14159...
<span>√ = square root
</span>
Formula: A = (1/4)na2 cot(π/n) = nr2 tan(π/n)
