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Wittaler [7]
2 years ago
11

Mrs. Allan's car uses 8 gallons of gas for a 224-mile trip. Mrs. Owen's car uses 6 gallons of gas for a 210-mile trip. How many

gallons of gas would each car use if both cars traveled 560 miles?
Mathematics
1 answer:
Feliz [49]2 years ago
8 0

Answer:

Mrs. Allan's Car will use <u>20 gallons</u> of gas for 560 miles trip.

Mrs. Owen's Car will use <u>16 gallons</u> of gas for 560 miles trip.

Step-by-step explanation:

Given:

Number of Miles for Mrs Allan car = 224 miles

Number of gallons of gas required = 8

We need to find the number of gallons of gas required for 560 miles for Mrs. Allan's car.

First we will find, in 1 gallons how many miles does Mrs Allan's Car drives.

For 8 gallons = 224 miles

So for 1 gallons = Number of miles in 1 gallon of gas

By using Unitary method we get;

Number of miles in 1 gallon of gas = \frac{224}{8}= 28\ miles

Now we know that;

for 28 miles = 1 gallon of gas is required.

So for 560 miles = Number of gallon of gas required in 560 miles.

Again by using Unitary method we get;

Number of gallon of gas required in 560 miles = \frac{560}{28}= 20\ gallons

Hence Mrs. Allan's Car will use <u>20 gallons</u> of gas for 560 miles trip.

Also Given:

Number of Miles for Mrs Owen's car = 210 miles

Number of gallons of gas required = 6

We need to find the number of gallons of gas required for 560 miles for Mrs. Owen's car.

First we will find, in 1 gallons how many miles does Mrs Owen's Car drives.

For 6 gallons = 210 miles

So for 1 gallons = Number of miles in 1 gallon of gas

By using Unitary method we get;

Number of miles in 1 gallon of gas = \frac{210}{6}= 35\ miles

Now we know that;

for 35 miles = 1 gallon of gas is required.

So for 560 miles = Number of gallon of gas required in 560 miles.

Again by using Unitary method we get;

Number of gallon of gas required in 560 miles = \frac{560}{35}= 16\ gallons

Hence Mrs. Owen's Car will use <u>16 gallons</u> of gas for 560 miles trip.

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(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
2 years ago
According to the Rational Root Theorem, the following are potential roots of f(x) = 6x4 + 5x3 – 33x2 – 12x + 20. -5/2,-2, 1, 10/
stiks02 [169]
-5/2 is the answer. I just took the test and got it right.
8 0
2 years ago
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Jennifer has a bag of chips that contains 2 red chips and 1 black chips. If she also has a fair die, what is the probability tha
borishaifa [10]
Find each probability separately and then multiply the two together


Probability for even number is 3/6 or 1/2 because their are 3 even numbers out of 6 numbers

Probability to get a black chip is 1 black chip out of 3 totals so 1/3

Multiply 1/3 by 1/2

Answer 1/6
5 0
2 years ago
Read 2 more answers
Triangle ABE is similar to triangle ACD. AED and ABC are straight lines. EB and DC are parallel. AE = 5 cm, BC = 4.5 cm, BE = 4
lianna [129]

Answer:

y = 16x/65

Step-by-step explanation:

Given:

Triangle ABE is similar to triangle ACD. AED and ABC are straight lines

EB and DC are parallel

The area of quadrilateral BCDE = xcm²

The area of triangle ABE = ycm²

Find attached the diagram from the above information.

In similar triangles, the ratio of their corresponding angles are equal.

Also, the ratio of the area of the two triangles = square of ratio of the corresponding sides of the two triangles.

Area ∆ACD/area of ∆ABE = (DC/EB)²

Area ∆ACD/area of ∆ABE = [(area of quadrilateral BCDE +

area of ∆ABE)]/(area of ∆ABE)

(x+y)/y = (DC/EB)²

(x+y)/y = (9/4)²

x+y = (81/16)y

x = (81/16)y - y

x = (81y - 16y)/16

x = 65y/16

Making y subject of formula

16x = 65y

y = 16x/65

An expression for y in terms of x:

y = 16x/65

3 0
1 year ago
A coin has a radius of 10 mm. How long will it take the coin to roll through the given angle measure at the given angular veloci
Gemiola [76]

Answer:

t = 1.57 sec

distance, d = 98.65 mm

Step-by-step explanation:

Given an angle of 540°

At 6 revolutions per second, which is the angular velocity.

Radius, r = 10 mm

We are asked to find the time and the distance.

To find the time, let's use the formula:

\theta = a*t

Where \theta = angle in radians.

Converting 540° to radians, we have:

\theta = 540 * \frac{\pi}{180} = 9.42 rad

Therefore, from the formula, let's find t.

\theta = a*t

9.42 = 6 * t

t = \frac{9.42}{6} = 1.57

time = 1.57

To find the distance, we have:

\frac{1.57 * 360}{360} = \frac{d}{2 \pi r}

\frac{1.57 * 360}{360} = \frac{d}{2\pi 10}

1.57 = \frac{d}{20\pi}

d = 20 \pi *1.57

d = 98.65 mm

Therefore, the time is 1.57 seconds and the distance is 98.65 mm

8 0
2 years ago
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