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inessss [21]
2 years ago
7

A function of the form f(x) = abx is modified so that the b value remains the same but the a value is increased by 2. How do the

domain and range of the new function compare to the domain and range of the original function? Check ALL that apply.
The range stays the same.
The range becomes y > 2.
The domain stays the same.
The domain becomes x > 2.
The range becomes y ≥ 2.
The domain becomes x ≥ 2.
Mathematics
2 answers:
bixtya [17]2 years ago
7 0

Answer:

The range stays the same.

and

The domain stays the same.  

Step-by-step explanation:

olga nikolaevna [1]2 years ago
6 0

Answer:

The range stays the same.

The domain stays the same.  

Step-by-step explanation:

The function f(x)=ab^{x} is an exponential function, where <em>a</em> is the coefficient, <em>b</em> is the base and <em>x</em> is the exponent.

The domain for this kind of functions is: All real numbers.

And the range is: (0,∞); this happen because the exponential functions are always positive when <em>a</em>>0.

Therefore, if the value of <em>a</em> is increased by 2, the domains will stay the same and the range will stay the same: (0,∞). The coefficient does not change the domain or the range if it keeps the same sign.

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Find the volume of a right circular cone that has a height of 12.5 cm and a base with a circumference of 5.8 cm. Round your answ
BaLLatris [955]

Answer:

V = 11.2 cm^3

Step-by-step explanation:

Given

Shape: Right Circular cone

Height, h = 12.5 cm

Base circumference, C = 5.8cm

Required:

Calculate Volume

The volume of a cone is calculated as thus;

Volume, V = \frac{1}{3}\pi r^2h

Where V, r and h represent the volume, the radius and the height of the cone respectively

But first we need to calculate the radius of the cone.

Using formula of circumference.

C = 2\pi r

We have C to be 5.8cm

By substituting this value;

5.8 = 2\pi r

Divide through by 2\pi

\frac{5.8}{2\pi} = \frac{2\pi r}{2\pi}

r = \frac{5.8}{2\pi}

r = \frac{2.9}{\pi}

Now, we can calculate the volume of the cone

By substituting r = \frac{2.9}{\pi} and h = 12.5 cm;

V = \frac{1}{3}\pi r^2h becomes

V = \frac{1}{3}\pi * (\frac{2.9}{\pi})^2 * 12.5

V = \frac{1}{3}\pi * \frac{8.41}{\pi^2} * 12.5

V = \frac{1}{3} * \frac{8.41}{\pi} * 12.5

Take \pi as 3.14

V = \frac{1}{3} * \frac{8.41}{3.14} * 12.5

V = 11.15976

V = 11.2 cm^3 ---- Approximated

Hence, the volume of the cone is; V = 11.2 cm^3

4 0
2 years ago
Se necesitan 4/7 de litro de pintura para pintar un metro cuadrado de pared, si queremos pintar 2/5 de metro cuadrado de pared,
Assoli18 [71]

Answer:

8/35 de litro

Step-by-step explanation:

De la pregunta, sabemos que se necesitan 4/7 de un litro para pintar un metro cuadrado de pared.

Ahora necesitamos saber la cantidad de pintura necesaria para pintar 2/5 de un metro cuadrado.

Digamos que la cantidad necesaria es x

Ahora hagamos una relación matemática;

4/7 pinturas 1 metro cuadrado

x pintará 2/5 metros

cuadrados por lo tanto, x * 1 = 4/7 * 2/5 = 8/35

6 0
2 years ago
The area of Norway is 24% more than the area of Colorado so Norway's area is-------% of Colorado's area
zhenek [66]
Possibly 124%.........
8 0
2 years ago
An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an
kotegsom [21]

Answer:

The mean number of successful surgeries is 1.57.

The variance of the number of successful surgeries is 0.3111.

Step-by-step explanation:

STEP 1

If the tear on the left knee has a rim width of less than 3mm, the probability that the surgery on the left knee will be successful (ls) is 0.90.

That isP(Is)=0.90

.

The probability that the surgery on the left knee will fail (lf) is 0.10. That isP(V)=0.10

.

If the tear on the right knee has a rim width of 3-6 mm, the probability that the surgery on the right knee will be successful (rs) is 0.67. That isP(rs)=0.67

.

The probability that the surgery on the right knee will fail (rf) is 0.33.

That isP(vf)= 0.33

.

Let the random variable X denote the number of successful surgeries. The range of X is{0,1,2)

.

Now find the probabilities associated with the possible values of X. The number of successful surgeries is equal to 0 if the surgeries on both knees fail. Since the surgeries are independent, we have:

P(X = 0)=P(lf and rf)

= P()P(rf)

=(0.10)(0.33)

= 0.033

The number of successful surgeries is equal to 1 if the surgery on one knee is successful and the surgery on the other knee fails, that is

P(X =1)= P((ls and rf) or (if and rs))

= P(Is)P(rf)+P(V)P(rs)

= (0.90)(0.33)+(0.10)(0.67)

= 0.364

The number of successful surgeries is equal to 2 if the surgeries on both knees are successful, that is

P(X = 2)=P(ls and rs)

= P(Is) P(rs)

=(0.90)(0.67)

= 0.603

So, the probability mass function of X is the following

X        0              1               2

f(x)     0.033      0.364      0.603

The mean number of successful surgeries is,

E(X)=∑xP(x)

=(0×0.033) +(1×0.364)+(2×0.603)

=1.57

the mean number of successful surgeries is 1.57

The expected value is obtained by taking the summation of the product of each possible value of the random variable X with its corresponding probabilities. Thus, the mean number of successful surgeries is 1.57.

STEP 2

The variance of the number of successful surgeries is,

Var(X)=∑x²P(x)-(E(x²)

=(0×0.033) + (1 × 0.364) +(2 × 0.603) - (1.57)²

= 2.776 -(1.57)²

=0.3111

The variance of the number of successful surgeries is 0.3111.

6 0
2 years ago
Holly bought 23 tickets to the baseball game. She got a group rate that gave her $4 off of the regular ticket price for each tic
sveticcg [70]

Answer:

The regular price of the ticket was $12.

Step-by-step explanation:

Let us call P the regular price of the tickets, and if she had bought tickets at this price, the total cost would have been

23P.

But Holly got $4 off the regular ticket price, that means one ticket cost her

P-4

and if she bought 23 tickets it cost her

23(P-4)

and we are told this equals $184; therefore we have

23(P-4)=184

now we solve this equation the following way:

23(P-4)=184

23P-4(23)=184

23P-92=184

23P=276

\boxed{ P=12}

Thus, the regular price was $12.

5 0
2 years ago
Read 2 more answers
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