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Sergeu [11.5K]
2 years ago
5

Let μ denote the true average radioactivity level(picocuries per liter). The value 5 pCi/L is considered thedividing line betwee

n safe and unsafe water. Would you recommend testing H0: μ = 5 vs Ha: μ > 5 or H0: μ =5 vs Ha: μ < 5?
Mathematics
1 answer:
VMariaS [17]2 years ago
7 0

Answer:

H0: μ = 5 versus Ha: μ < 5.

Step-by-step explanation:

Given:

μ = true average radioactivity level(picocuries per liter)

5 pCi/L = dividing line between safe and unsafe water

The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.

A type I error, is an error where the null hypothesis, H0 is rejected when it is true.

We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.

Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.

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Show that the three points whose position vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k form an isosceles right
Novay_Z [31]

Answer:

AB = √18 , BC=√18 and CA =4

AB²+BC²  = CA² and AB=BC

ΔABC isosceles right  angled triangle.

Step-by-step explanation:

Given vectors are  7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k

A( 0,7,10), B( -1,6,6) C(-4,9,6)

AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k

AB = \sqrt{1+1+16} = \sqrt{18}

BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j

BC=\sqrt{9+9} =\sqrt{18}

CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k

CA = \sqrt{16+4+16} =\sqrt{36} =4

Since AB²+BC²  = CA²

And AB=BC

Therefore it follows that ΔABC is a right angled isosceles triangle



3 0
2 years ago
Baileigh is using a piece of string to hang a painting on the wall. The back of the painting is diagrammed below. 12 cm 12 cm 5
Nutka1998 [239]
HI THE ANSWER IS 26CM

6 0
2 years ago
the performance score of 10 adults is recorded, and the results are 83 87 90 92 93 100 104 111 115 121 find the standard deviati
luda_lava [24]

Answer:

The standard deviation of the data set is \sigma = 12.7906.

Step-by-step explanation:

The Standard Deviation is a measure of how spread out numbers are. Its symbol is σ (the greek letter sigma)

To find the standard deviation of the following data set

\begin{array}{cccccccc}83&87&90&92&93&100&104&111\\115&121&&&&&&\end{array}

we use the following formula

                                             \sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} }

Step 1: Find the mean \left( \overline{X} \right).

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

                                     Mean = \frac{Sum ~ of ~ terms}{Number ~ of ~ terms}

Mean = \frac{Sum ~ of ~ terms}{Number ~ of ~ terms}=\frac{83+87+90+92+93+100+104+111+115+121}{10} \\\\Mean = \frac{996}{10} =\frac{498}{5}=99.6

Step 2: Create the below table.

Step 3: Find the sum of numbers in the last column to get.

\sum{\left(x_i - \overline{X}\right)^2} = 1472.4

Step 4: Calculate σ using the above formula.

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 1472.4 }{ 10 - 1} } \approx 12.7906

3 0
2 years ago
The random variable X, representing the number of cherries in a cherry puff, has the following probability distribution:x: 4 - 5
marta [7]

Answer:

Step-by-step explanation:

Given is the probability distribution of a random variable X

X 4 5 6 7 Total

P 0.2 0.4 0.3 0.1 1

x*p 0.8 2 1.8 0.7 5.3

x^2*p 3.2 10 10.8 4.9 28.9

a) E(X) = Mean of X = sum of xp = 5.3

Var(x) = 28.9-5.3^2=0.81

Std dev = square root of variance = 0.9

------------------------------------

b) For sample mean we have

Mean = 5.3

Variance = var(x)/n = \frac{0.81}{{36} } \\=0.0225

c) P(\bar X

3 0
2 years ago
If f (x) = StartRoot 4 x + 9 EndRoot + 2, which inequality can be used to find the domain of f(x)? StartRoot 4 x EndRoot greater
maxonik [38]

Answer:

Step-by-step explanation:

"f (x) = StartRoot 4 x + 9 EndRoot + 2" should be written as

 

Note that √(4x + 9) is a variation of the basic function y = √x, whose domain is [0, ∞ ).

The domain of f(x) = √(4x + 9) + 2 is found by taking the "argument" 4x + 9 of √(4x + 9) and setting it equal to zero:

4x + 9 ≥ 0, or

4x ≥ -9, or

x ≥ -9/4

This is the domain of the given function f(x) = √(4x + 9) + 2.  So long as x is ≥ -9/4, the function f(x) will be defined.

6 0
2 years ago
Read 2 more answers
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