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2 years ago

The two dot plots below compare the forearm lengths of two groups of schoolchildren:

2 answers:

7 0

B.

as a, none is longer than 11 inches
b, 2 are longer than 11 inches
c, 3 have 9 inches (which is the shortest)
s, one has 9 inches

Solnce55 [7]2 years ago

3 0

Two dot plots are shown one below the other. The title for the top dot plot is Online Customers and the title for the bottom plot is Walk-In Customers. Below the line for each dot plot is written Number of Packs. There are markings from 1 to 5 on each line at intervals of one. For the top line there are 0, 0, 1, 5, 4 dots respectively for marks from 1 to 5. For the bottom line there are 6, 3, 1, 0, 0 dots respectively for marks from 1 to 5.

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Rex walks 3 1/7 km in 1 1/4 hours. At the same speed , how long will he go in one hour? Simplify your answer and write it as a p

Llana [10]

She walks 22/7 km in 5/4 hrs, so she walks (22/7)/(5/4) km, or 88/35 (2_18/35) km, in 1 hr.

7 0

2 years ago

If a hurricane was headed your way, would you evacuate? The headline of a press release states, "Thirty-four Percent of People o

IgorC [24]

Answer:

The 98% confidence interval would be given by (0.326;0.354)

Step-by-step explanation:

1) Notation and definitions

$X=63$ number of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

$n=6138$ random sample taken

$\hat p=0.34$ estimated proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

$p$ true population proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

2) Confidence interval

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 98% of confidence, our significance level would be given by $\alpha=1-0.98=0.02$ and $\alpha/2 =0.01$ . And the critical value would be given by:

$z_{\alpha/2}=-2.33, z_{1-\alpha/2}=2.33$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.34 - 2.33\sqrt{\frac{0.34(1-0.34)}{6138}}=0.326$

$0.34 + 2.33\sqrt{\frac{0.34(1-0.34)}{6138}}=0.354$

The 98% confidence interval would be given by (0.326;0.354)

8 0

2 years ago

Fatima saved $15,000 toward a down payment on a house. She makes $5,375 a month. What is the maximum loan she can take on a hous

Fittoniya [83]

We will use $\frac{28}{36}$ ratio to determine how much can Fatima afford as a loan for her house.

Let gross income of Fatima = $ x

Amount earned by Fatima monthly= $ 5,375

36 % of 5,375=

$\frac{36}{100}\times 5,375=1935$ $

Maximum amount that can be paid as a loan monthly = $ 1935

Total money that she can pay yearly for house loan if Fatima allowable money for paying loans is $ 1935=

$1935 \times 12=23220$ $

Money saved as a down payment = $ 15,000

So, maximum amount loan Fatima can take on a house= 23220 + 15000=$38,220

She is not allowed for loan for house if the cost of house is any of the four options.

(B) 28 % of $ 5375=

$\frac{28}{100}\times 5,375=1505$ $

Maximum amount that Fatima spend on her house monthly= $ 1505

Amount that fatima can spend yearly on her house = 1505× 12 =$18,060

For the four options given , none of the option matches Fatima's expectations.

7 0

2 years ago

Read 2 more answers

Find the common difference of the arithmetic sequence. 6,9.4,12.8,16.2

Blababa [14]

A sequence is said to be arithmetic if every couple of adjacent elements differ by the same number. If this is the case, that constant number is called the common difference.

This sequence is arithmetic, because the difference between every element and the previous one is