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jasenka [17]
2 years ago
15

The two dot plots below compare the forearm lengths of two groups of schoolchildren:

Mathematics
2 answers:
Oliga [24]2 years ago
7 0
B.

as a, none is longer than 11 inches
b, 2 are longer than 11 inches
c, 3 have 9 inches (which is the shortest)
s, one has 9 inches
Solnce55 [7]2 years ago
3 0

Two dot plots are shown one below the other. The title for the top dot plot is Online Customers and the title for the bottom plot is Walk-In Customers. Below the line for each dot plot is written Number of Packs. There are markings from 1 to 5 on each line at intervals of one. For the top line there are 0, 0, 1, 5, 4 dots respectively for marks from 1 to 5. For the bottom line there are 6, 3, 1, 0, 0 dots respectively for marks from 1 to 5.

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the required condition for using an anova procedure on data from several populations for mean comparison is that the
Anuta_ua [19.1K]

Answer:

The sampled populations have equal variances

Step-by-step explanation:

ANOVA which is fully known as Analysis of variances can be defined as the collection of statistical models as well as their associated estimation procedures which enables easily and effectively analyzis of the differences among various group means in a sample reason been that ANOVA is a total variance in which the observed variance in a specific variable is been separated into components which are attributable to various sources of variation which is why ANOVA help to provides a statistical test to check whether two or more population means are equal.

Therefore the required condition for using an ANOVA procedure on data from several populations for mean comparison is that THE SAMPLED POPULATION HAVE EQUAL VARIANCE.

5 0
2 years ago
In one baseball season Peter hit twice the difference of the number of home runs Alice hit and 6. altogether,they hit 18 home ru
Viktor [21]
<span>In a baseball season:
Peter hit = 2 (x - 6)
Total = 19 hits

X= Alex’s hit
Y = Peter’s Hit

=> Y = 2(x - 6)
=> x + y = 18
Let’s start from the second given equation:
=> x + y =18
=> y = 18 – x
Now, let’s use the first given equation to solve:
=> 18 – x = 2 (x - 6)
=> 18 – x = 2x – 12
=> -3x = -30
x = 10

Now, Let’s try:
=> Y = 2(x - 6)
=> y = 2 (10 - 6)
=> y = 2 (4)
=> y = 8

Thus, Peter hit 8 and Alice hit 10.</span>



4 0
2 years ago
Jonah’s restaurant bill comes to $25.65 and he leaves a 15% tip. What’s the total costof his restaurant bill?
crimeas [40]
His total bill will be roughly 29.50

6 0
2 years ago
Read 2 more answers
Circle C has radius of 10 cm. Each of points B and D is on the midpoint of the radius. Find the area of the shaded region.
olya-2409 [2.1K]
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
7 0
2 years ago
Read 2 more answers
What is the probability that a point chosen at random in the triangle is also in the blue square? A blue square inside of an uns
Dmitrij [34]

Answer:

One-third

Step-by-step explanation:

we know that

The probability that a point chosen at random in the triangle is also in the blue square is equal to divide the area of the square by the area of triangle

step 1

Determine the area of triangle

A=\frac{1}{2}(9)(6)=27\ in^2

step 2

Determine the area of the square

A=(3^2)=9\ in^2

step 3

Determine the probability

P=\frac{9}{27}

simplify

P=\frac{1}{3}

therefore

One-third

5 0
2 years ago
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