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2 years ago

Evaluate 1/3 m - 1 - 1/2 n when m = 21 and n = 12

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

3 0

Answer:

Step-by-step explanation:

1/3(21)-1-1/2(12)

7-1-6=6-6=0

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Agata [3.3K]

Answer:

B. $3927.54

Step-by-step explanation:

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2 years ago

There are 10 pots exposed in the shop, 2 of which have hidden defects. the customer buys two pieces. what is the probability tha

Tpy6a [65]

Check the tree diagram, of all the possible scenarios and the probabilities.

All the possible scenarios are:

1st.non defective, 2nd.non defective
1st.non defective, 2nd. defective
1st. defective, 2nd. non defective
1st. defective, 2nd. defective

consider the case 1st.non defective, 2nd.non defective

the probability that the first one is non defective is 8/10, since 8 out of 10 are non defective.

In this scenario, the second one is non defective as well. The probability for this to happen is 7/9, since now we have 7 non defective pots, and 9 in total.

This means that the probability of the first to be non defective, and the second non-defective is (8/10) * (7/9)=0.622

similarly we calculate the other cases, as shown in the picture.

P(at least one is defective)=
P(1st.non defective, 2nd. defective)+P(1st. defective, 2nd. non defective)+P(1st. defective, 2nd. defective)=
0.178+0.178+0.022=0.378

Answer: 0.378

8 0

2 years ago

What is the solution for x in the equation? -4 + 5x − 7 = 10 + 3x − 2x A. B. C. D.

laiz [17]

Answer:

x=21/4

Step-by-step explanation:

1. combine like terms

-4+-7= -11 3x-2x=x

2. subtract x

5x-11=x+10

4x-11=10

3. add 11

4x=21

4. divide 21 by 4 = 21/4

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2 years ago

Each airline passenger and his or her luggage must be checked to determine whether he or she is carrying weapons on to the airpl

Dafna1 [17]

Answer:

$P_k = 0.83$

$N_{\mu} \approx 4 \ passengers$

$T_{\lambda} = 0.5 \ minutes$

Step-by-step explanation:

From the question we are told that

The average number of passengers that arrive per minute is $\lambda = 10$

The average number of check that can be carried out in one minute is $\mu= 12$

Generally the probability that a passenger will have to wait before being checked for weapons is mathematically represented as

$P_k = \frac{\lambda }{ \mu }$

=> $P_k = \frac{10 }{ 12}$

=> $P_k = 0.83$

Generally the number of passengers are waiting in line to enter the checkpoint is mathematically represented as

$N_{\mu} = \frac{\lambda^2}{\mu (\mu -\lambda) }$

=> $N_{\mu} = \frac{10^2}{12 (12 -10) }$

=> $N_{\mu} \approx 4 \ passengers$

Generally the average time a passenger spend at the checkpoint is mathematically represented as

$T_{\lambda} = \frac{ \frac{\lambda}{(\mu - \lambda)} }{ \lambda}$

=> $T_{\lambda} = \frac{ \frac{ 10}{(12 - 10)} }{10}$

=> $T_{\lambda} = 0.5 \ minutes$

5 0

1 year ago

6x6x6x6x6x6x6=6x whats the value of x

Oksi-84 [34.3K]

Answer: 46656

Step-by-step explanation: there are 7 x’s on the left side of the equation, and one on the right. The one on the right side is multiplied to a variable, x. Divide both sides by 6, you get 6 6 times on the left side. Multiply and you get 46656

4 0

2 years ago

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